1Z0-007
NOTE: Marked with Red are correct answers.
Questions marked with Dark Blue
were asked in the paper on 04th Oct, 2004.
1. Which of the following queries can you use to search
for employees with the pattern 'A_B' in their names?
A. SELECT last_name FROM employees WHERE last_name LIKE
'%A\_B%' ESCAPE '\\';
B. SELECT last_name FROM employees WHERE last_name LIKE
'%A_B%' ESCAPE;
C. SELECT last_name FROM employees WHERE last_name LIKE
'A_B%' ESCAPE '%';
D. SELECT last_name FROM employees WHERE last_name
LIKE '%A\_B%' ESCAPE '\';
2. Refer to the SQL codes below:
SELECT manager_id, last_name, hire_date, salary, AVG
(salary) OVER (PARTITION BY manager_id ORDER BY hire_date ROWS BETWEEN 1
PRECEDING AND 1 FOLLOWING) AS C_mavg FROM employees;
What has been achieved?
A. because of a syntax problem, no
row will be returned
B. it calculates, for each employee in the employees table, the average salary of the employees reporting to his/her respective manager
C. it calculates, for each employee in the employees table, the average salary of the employees reporting to his/her respective manager who were hired just before the employee
D. it calculates, for each employee in the employees table, the average salary of the employees reporting to the same manager who were hired in the range just before through just after the employee
E. it calculates, for each employee in the employees table, the average salary of the employees reporting to his/her respective manager who were hired just after the employee
B. it calculates, for each employee in the employees table, the average salary of the employees reporting to his/her respective manager
C. it calculates, for each employee in the employees table, the average salary of the employees reporting to his/her respective manager who were hired just before the employee
D. it calculates, for each employee in the employees table, the average salary of the employees reporting to the same manager who were hired in the range just before through just after the employee
E. it calculates, for each employee in the employees table, the average salary of the employees reporting to his/her respective manager who were hired just after the employee
3. with 9i SQL Plus, What kinds of commands can you enters
at the command prompt (Choose all that apply)?
A. PL/SQL blocks
B. SQL*Plus commands
C. security commands
D. SQL commands
4. to write a query that performs an outer join of tables
A and B and returns all rows from B, You need to write
- any outer join
- a left outer join
- a cross join
- a right outer join
- an inner join
5. Which of the following is true if you use the alter
tablespace statement and specify the TEMPORARY clause (Choose all that apply)?
- Oracle no longer perform any checkpoint for the online datafiles in the tablespace
- Oracle performs a checkpoint for all online datafiles in the tablespace
- Oracle does not ensure that all files are written
- The offline files may require media recovery before you bring the tablespace online
- E. The offline files may require media recovery after you bring the tablespace online
6. Which of the following correctly shows the correct use
of the TRUNC command on a date?
- SELECT TRUNC(TO_DATE(12-Feb-99,DD-MON-YY, 'YEAR')) "Date " FROM DUAL;
- TRUNC = TO_DATE('12-Feb-99','DD-MON-YY'), 'YEAR', "Date " FROM DUAL;
- SELECT TRUNC(TO_DATE('12-Feb-99','DD-MON-YY'), 'YEAR') "Date " FROM DUAL;
- date = TRUNC(TO_DATE('12-Feb-99','DD-MON-YY'), 'YEAR') "Date " FROM DUAL
7. To grant a system privilege with the GRANT statement,
you must (Choose all that apply)?
- have been granted the GRANT ROLE PRIVILEGE system privilege
- have been granted the system privilege with the ADMIN OPTION
- have been granted the GRANT ANY PRIVILEGE system privilege
- have been granted the system privilege with the GRANT OPTION
8. Which of the following are the conditions that must be
met before you can use RENAME DATAFILE with the alter tablespace command
(Choose all that apply)?
- the datafile must be taken offline before renaming
- the database must be open
- when only a single datafile is to be renamed
- when only a single datafile on the same drive is to be renamed
9. Before making a tablespace read only, which of the
following conditions must be met (Choose all that apply)?
- The tablespace must contain an active rollback segments.
- The tablespace must be online.
- The tablespace must not contain any active rollback segments.
- The tablespace must not be involved in an open backup.
- The tablespace must be involved in an open backup.
10. The MANAGE TABLESPACE system privilege allows you to
perform which of the following operations (Choose all that apply)?
A. Take the tablespace
offline
B. Begin a backup
C. End a backup
D. Take the tablespace online
E. Make the tablespace
read only
F. Make the tablespace
read write
11. Which of the following has been achieved by the
following SQL codes? SELECT employee_id FROM employees WHERE commission_pct =
.5 OR salary > 23000;
- it returns employees who have a 50% of a salary greater than $23,000:
- it returns employees who have a 50% commission rate or a salary greater than $23,000:
- runtime error
- it returns employees who have a 50% of a salary less than $23,000:
- invalid syntax
- it returns employees who have a 50% commission rate and a salary greater than $23,000:
12. Which of the following has been achieved by the
following SQL codes? SELECT * FROM employees WHERE hire_date < TO_DATE
('01-JAN-1999', 'DD-MON-YYYY') AND salary > 3500;
- only those hired before 1999 and earning less than $3500 a month are returned
- compile time error
- only those hired after 1999 and earning more than $3500 a month are returned
- runtime error
- only those hired before 1999 and earning more than $3500 a month are returned
13. Which of the following SQL statements can calculate
and return the absolute value of -33?
- SELECT ABS("-33") Absolute FROM DUAL;
- SELECT ABS('-33') "Absolute" FROM DUAL;
- SELECT ABS(-33) "Absolute" FROM DUAL;
- SELECT ABS(-33), Absolute FROM DUAL;
14. Which two statements about
Subqueries are true? (Choose two.)
- A single row subquery can retrieve data from only one table.
- A SQL query statement cannot display data from table B that is referred to in its subquery, unless table B is included in the main query's FROM clause.
- A SQL query statement can display data from table B that is referred to in its subquery, without including table B in its own FROM clause.
- A single row subquery can retrieve data from more than one table.
- A single row subquery cannot be used in a condition where the LIKE operator is used for comparison.
- A multiple-row subquery cannot be used in a condition where the LIKE operator is used for comparison.
15 Examine the description of
the STUDENTS table:
STD_ID NUMBER (4)
COURSE_ID VARCHAR2 (10)
START_DATE
DATE
END_DATE DATE
Which two
aggregate functions are valid on the START_DATE column? (Choose two)
- SUM(start_date)
- AVG(start_date)
- COUNT(start_date)
- AVG(start_date, end_date)
- MIN(start_date)
- MAXIMUM(start_date)
16. Examine the structure of the
EMP_DEPT_VU view:
Column Name Type
Remarks
EMPLOYEE_ID NUMBER
From the EMPLOYEES table:
EMP_NAME VARCHAR2
(30)
JOB_ID VARCHAR2
(20)
SALARY NUMBER
DEPARTMENT_ID NUMBER
From the DEPARTMENTS table:
DEPT_NAME VARCHAR2 (30)
Which SQL statement produces an error?
- SELECT * FROM emp_dept_vu;
- SELECT department_id, SUM(salary) FROM emp_dept_vu GROUP BY department_id;
- SELECT department_id, job_id, AVG(salary) FROM emp_dept_vu GROUP BY department_id, job_id;
- SELECT job_id, SUM(salary) FROM emp_dept_vu WHERE department_id IN (10,20) GROUP BY job_id HAVING SUM(salary) > 20000;
- None of the statements produce an error; all are valid.
17. Examine the description of
the EMPLOYEES table:
EMP_ID NUMBER (4) NOT
NULL
LAST_NAME VARCHAR2
(30) NOT NULL
FIRST_NAME VARCHAR2
(30)
DEPT_ID NUMBER
(2)
JOB_CAT VARCHAR
(30)
SALARY NUMBER
(8, 2)
Which statement shows the department ID, minimum salary,
and maximum salary paid in that department, only if the minimum salary is less
than 5000 and maximum salary is more than 15000?
- SELECT dept_id, MIN (salary), MAX (salary) FROM employees WHERE MIN(salary) < 5000 AND MAX (salary) > 15000;
- SELECT dept_id, MIN (salary), MAX (salary) FROM employees WHERE MIN (salary) < 5000 AND MAX (salary) 15000 GROUP BY dept_id;
- SELECT dept_id, MIN(salary), MAX(salary) FROM employees HAVING MIN (salary) < 5000 AND MAX (salary)
- SELECT dept_id, MIN (salary), MAX (salary) FROM employees GROUP BY dept_id HAVING MIN(salary) < 5000 AND MAX (salary) > 15000
- SELECT dept_id, MIN (salary), MAX (salary) FROM employees GROUP BY dept_id, salary HAVING MIN (salary) < 5000 AND MAX (salary) > 15000;
18. You own a table called EMPLOYEES with this table
structure:
EMPLOYEE_ID NUMBER
Primary Key
FIRST_NAME VARCHAR2
(25)
LAST_NAME VARCHAR2
(25)
HIRE_DATE DATE
What happens when you execute this DELETE statement?
DELETE employees;
A. You
get an error because of a primary key violation.
- The data and structure of the EMPLOYEES table are deleted.
- The data in the EMPLOYEES table is deleted but not the structure.
- You get an error because the statement is not syntactically correct.
19. Evaluate this SQL statement:
SELECT e.employee_id, (.15* e.salary) + (.5 *
e.commission_pct) + (s.sales_amount * (.35 * e.bonus)) AS CALC_VALUE FROM
employees e, sales WHERE e.employee_id = s.emp_id;
What will happen if you remove all the parentheses from
the calculation?
- The value displayed in the CALC_VALUE column will be lower.
- The value displayed in the CALC_VALUE column will be higher.
- There will be no difference in the value displayed in the CALC_VALUE column.
- An error will be reported.
20. Examine the structure of the EMPLOYEES and
NEW_EMPLOYEES tables:
EMPLOYEES:
EMPLOYEE_ID NUMBER
Primary Key
FIRST_NAME VARCHAR2
(25)
LAST_NAME VARCHAR2
(25)
HIRE_DATE DATE
NEW_EMPLOYEES:
EMPLOYEE_ID NUMBER
Primary Key
NAME VARCHAR2
(60)
Which
MERGE statement is valid?
- MERGE INTO new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT VALUES (e.employee_id, e.first_name ||', '||e.last_name);
- MERGE new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN EXISTS THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT VALUES (e.employee_id, e.first_name ||', '||e.last_name);
- MERGE INTO new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN EXISTS THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT VALUES(e.employee_id, e.first_name ||', '||e.last_name);
- MERGE new_employees c FROM employees e ON (c.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT INTO new_employees VALUES (e.employee_id, e.first_name ||', '||e.! last_name);
21 .The EMPLOYEES table contains these columns:
EMPLOYEE_ID NUMBER(4) ENAME VARCHAR2 (25) JOB_ID VARCHAR2(10) Which SQL
statement will return the ENAME, length of the ENAME, and the numeric position
of the letter "a" in the ENAME column, for those employees whose
ENAME ends with a the letter "n"?
- SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, 'a') FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
- SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, ,-1,1) FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
- SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, 1, 1) = 'n';
- SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, -1, 1) = 'n';
22. You would like to display the system date in
the format "Monday, 01 June, 2001". Which SELECT statement should you
use?
- SELECT TO_DATE (SYSDATE, 'FMDAY, DD Month, YYYY') FROM dual;
- SELECT TO_CHAR (SYSDATE, 'FMDD, DY Month, YYYY') FROM dual;
- SELECT TO_CHAR (SYSDATE, 'FMDay, DD Month, YYYY') FROM dual;
- SELECT TO_CHAR (SYSDATE, 'FMDY, DDD Month, YYYY') FROM dual;
- SELECT TO_DATE (SYSDATE, 'FMDY, DDD Month, YYYY') FROM dual;
23. What is true about joining tables through an
Equijoin?
- You can join a maximum of two tables through an Equijoin.
- You can join a maximum of two columns through an Equijoin.
- You specify an Equijoin condition in the SELECT or FROM clauses of a SELECT statement.
- To join two tables through an Equijoin, the columns in the join condition must be primary key and foreign key columns.
- You can join n tables (all having single column primary keys) in a SQL statement by specifying a minimum of n-1 join conditions.
24. Which four are valid Oracle constraint types? (Choose
four.)
A. CASCADE
B. UNIQUE
C. NONUNIQUE
D. CHECK
E. PRIMARY KEY
F. CONSTANT
G. NOT NULL
25. View the image below to examine the structures of the
EMPLOYEES and TAX tables.
You need to find the percentage tax applicable for each
employee. Which SQL statement would you use?
- SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE e.salary BETWEEN t.min_salary AND t.max_salary;
- SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE e.salary > t.min_salary AND < t.max_salary;
- SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE MIN(e.salary) = t.min_salary AND MAX(e.salary) = t.max_salary;
- You cannot find the information because there is no common column between the two tables.
26. Click the Exhibit button to examine the structures of
the EMPLOYEES, DEPARTMENTS and LOCATIONS tables. EMPLOYEES EMPLOYEE_ID NUMBER
NOT NULL, Primary Key EMP NAME VARCHAR2 (30)
JOB_ID VARCHAR2 (20)
SALARY NUMBER
MGR_ID NUMBER References EMPLOYEE_ID column DEPARTMENT_ID
NUMBER Foreign key to DEPARTMNET_ID column of the DEPARTMENTS table DEPARTMENTS
DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2 (30)
MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table
LOCATION_ID NUMBER Foreign key to LOCATION_ID column of the LOCATIONS table
LOCATIONS LOCATIONS_ID NUMBER NOT NULL, Primary Key CITY VARCHAR2(30)
Which two SQL statements produce the; name, department
name, and the city of all the employees who earn more than 10000? (Choose Two).
- SELECT emp_name, department_name, city FROM employees e JOIN departments d USING (department_id) JOIN locations 1 USING (location_id) WHERE salary > 10000;
- SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 JOIN ON (e. department_id = d. department id) AND (d.location_id = 1.location_id) AND salary > 10000;
- SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE salary > 1000;
- SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE e.department_id = d.department_id AND d.location_id = 1.location_id AND salary > 10000;
- SELECT emp_name, department_name, city FROM employees e NATURAL JOIN departments, locations WHERE salary > 10000;
Answer: AD........BD
27. Which SQL statement would you use to remove a view
called EMP_DEPT_VU from your schema?
A. DROP emp_dept_vu;
B. DELETE emp_dept_vu;
C. REMOVE emp_dept_vu;
D. DROP VIEW emp_dept_vu;
E. DELETE VIEW emp_dept_vu;
F. REMOVE VIEW emp_dept_vu;
28. Which is an iSQL*Plus
command?
A. INSERT
B. UPDATE
C. SELECT
D. DESCRIBE
E. DELETE
F. RENAME
29. The EMPLOYEES table has
these columns:
LAST_NAME VARCHAR2
(35)
SALARY NUMBER
(8, 2)
HIRE_DATE DATE
Management wants to add a default value to the SALARY
column. You plan to alter the table by using this SQL statement:
ALTER TABLE EMPLOYEES MODIFY (SALARY DEFAULT 5000);
Which is true about your ALTER statement?
- Column definitions cannot be altered to add DEFAULT values.
- A change to the DEFAULT value affects only subsequent insertions to the table.
- Column definitions cannot be altered to add DEFAULT values for columns with a NUMBER data type.
- All the rows that have a NULL value for the SALARY column will be updated with the value 5000.
30. Examine the description of
the EMPLOYEES table:
EMP_ID NUMBER
(4) NOT NULL
LAST_NAME VARCHAR2
(30) NOT NULL
FIRST_NAME VARCHAR2
(30)
DEPT_ID NUMBER
(2)
Which statement produces the number of different
departments that have employees with last name Smith?
- SELECT COUNT(*) FROM employees WHERE last_name='Smith';
- SELECT COUNT (dept_id) FROM employees WHERE last_name='Smith';
- SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';
- SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';
- SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';
31. Which SELECT statement should you use to extract the
year from the system date and display it in the format "1998"?
- SELECT TO_CHAR(SYSDATE, 'yyyy') FROM dual;
- SELECT TO_DATE(SYSDATE, 'yyyy') FROM dual;
- SELECT DECODE(SUBSTR(SYSDATE, 8), 'YYYY') FROM dual;
- SELECT DECODE(SUBSTR(SYSDATE, 8), 'year') FROM dual;
- SELECT TO_CHAR(SUBSTR(SYSDATE, 8,2),'yyyy') FROM dual;
32. The STUDENT_GRADES table has these columns:
STUDENT_ID NUMBER
(12)
SEMESTER_END DATE
GPA NUMBER
(4, 3)
Which statement finds students who have a grade point
average (GPA) greater than 3.0 for the calendar year 2001?
- SELECT student_id, gpa FROM student_grades WHERE semester_end BETWEEN '01-JAN-2001' AND '31-DEC-2001' OR gpa > 3.0;
- SELECT student_id, gpa FROM student_grades WHERE semester_end BETWEEN '01-JAN-2001' AND '31-DEC-2001' AND gpa > 3.0;
- SELECT student_id, gpa FROM student_grades WHERE semester_end BETWEEN '01-JAN-2001' AND '31-DEC-2001' AND gpa > 3.0;
- SELECT student_id, gpa FROM student_grades WHERE semester_end BETWEEN '01-JAN-2001' AND '31-DEC-2001' AND gpa >= 3.0;
- SELECT student_id, gpa FROM student_grades WHERE semester_end > '01-JAN-2001' OR semester_end < '31-DEC-2001' AND gpa >= 3.0;
33. Top N analysis requires _____ and _____.
(Choose two.)
A. the use of rowed
B. a GROUP BY clause
C. an ORDER BY clause
D. only an inline view
E. an inline view and an outer query
34. Which are DML statements?
(Choose all that apply.)
A. COMMIT
B. MERGE
C. UPDATE
D. DELETE
E. CREATE
F. DROP
35. Which three is true
regarding the use of outer joins? (Choose three.)
- You cannot use IN operator in a condition that involves an outer join.
- You use (+) on both sides of the WHERE condition to perform an outer join.
- You use (*) on both sides of the WHERE condition to perform an outer join.
- You use an outer join to see only the rows that do not meet the join condition.
- In the WHERE condition, you use (+) following the name of the column in the table without matching rows, to perform an outer join.
- You cannot link a condition that is involved in an outer join to another condition by using the OR operator.
36. Which statement adds a constraint that ensures the
CUSTOMER_NAME column of the CUSTOMERS table holds a value?
- ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;
- ALTER TABLE customers MODIFY CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;
- ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn NOT NULL;
- ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn IS NOT NULL;
- ALTER TABLE customers MODIFY name CONSTRAINT cust_name_nn NOT NULL;
- ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name NOT NULL;
37. Evaluate this SQL statement:
SELECT ename, sal, 12*sal+100 FROM EMP;
The SAL column stores the monthly salary of the employee.
Which change must be made to the above syntax to calculate the annual
compensation as "monthly salary plus a monthly bonus of $100, multiplied
by 12"?
- No change is required to achieve the desired results.
- SELECT ename, sal, 12*(sal+100) FROM emp;
- SELECT ename, sal, (12*sal)+100 FROM emp;
- SELECT ename, sal+100,*12 FROM emp;
38. You are the DBA for an academic database. You
need to create a role that allows a group of users to modify existing rows in
the STUDENT_GRADES table.
Which set of statements accomplishes this?
A. CREATE
ROLE registrar; GRANT MODIFY ON student_grades TO registrar; GRANT registrar to
user1, user2, user3
- CREATE NEW ROLE registrar; GRANT ALL ON student_grades TO registrar; GRANT registrar to user1, user2, user3
- CREATE ROLE registrar; GRANT UPDATE ON student_grades TO registrar; GRANT ROLE registrar to user1, user2, user3
- CREATE ROLE registrar; GRANT UPDATE ON student_grades TO registrar; GRANT registrar to user1, user2, user3;
- E. CREATE registrar; GRANT CHANGE ON student_grades TO registrar; GRANT registrar;
39. You need to modify the STUDENTS table to add
a primary key on the STUDENT_ID column. The table is currently empty.
Which statement accomplishes this task?
- ALTER TABLE students ADD PRIMARY KEY student_id;
- ALTER TABLE students ADD CONSTRAINT PRIMARY KEY (student_id);
- ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY student_id;
- ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY (student_id);
- ALTER TABLE students MODIFY CONSTRAINT stud_id_pk PRIMARY KEY (student_id);
40. The STUDENT_GRADES table has these columns:
STUDENT_ID NUMBER
(12)
SEMESTER_END DATE
GPA NUMBER
(4, 3)
The registrar requested a report listing the students' grade
point averages (GPA) sorted from highest grade point average to lowest. Which
statement produces a report that displays the student ID and GPA in the sorted
order requested by the registrar?
- SELECT student_id, gpa FROM student_grades ORDER BY gpa ASC;
- SELECT student_id, gpa FROM student_grades SORT ORDER BY gpa ASC;
- SELECT student_id, gpa FROM student_grades SORT ORDER BY gpa;
- SELECT student_id, gpa FROM student_grades ORDER BY gpa;
- SELECT student_id, gpa FROM student_grades SORT ORDER BY gpa DESC;
- SELECT student_id, gpa FROM student_grades ORDER BY gpa DESC;
41. Which describes the default behavior when you create
a table?
- The table is accessible to all users.
- Tables are created in the public schema.
- Tables are created in your schema.
- Tables are created in the DBA schema.
- You must specify the schema when the table is created.
42. Which four are attributes of single row functions?
(Choose four.)
- cannot be nested
- manipulate data items
- act on each row returned
- return one result per row
- accept only one argument and return only one value
- accept arguments which can be a column or an expression
43. Which statement creates a new user?
- CREATE USER Susan;
- CREATE OR REPLACE USER Susan;
- CREATE NEW USER Susan DEFAULT;
- CREATE USER Susan IDENTIFIED BY blue;
- CREATE NEW USER Susan IDENTIFIED by blue;
- CREATE OR REPLACE USER Susan IDENTIFIED BY blue;
44. You need to create a table named ORDERS that contains
four columns: - an ORDER_ID column of number data type - a CUSTOMER_ID column
of number data type - an ORDER_STATUS column that contains a character data
type - a DATE_ORDERED column to contain the date the order was placed. When a
row is inserted into the table, if no value is provided for the status of the
order, the value PENDING should be used instead. Which statement accomplishes
this?
- CREATE TABLE orders (order_id NUMBER(10), customer_id NUMBER(8), order_status NUMBER(10) DEFAULT 'PENDING', date_ordered DATE );
- CREATE TABLE orders (order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );
- CREATE OR REPLACE TABLE orders (order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );
- CREATE OR REPLACE TABLE orders (order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );
- CREATE TABLE orders (order_id NUMBER(10), customer_id NUMBER(8),order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );
- CREATE TABLE orders (order_id NUMBER(10), customer_id NUMBER(8),order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered VARCHAR2 );
45.
Which two statements complete a transaction? (Choose two.)
- DELETE employees;
- DESCRIBE employees;
- ROLLBACK TO SAVEPOINT C;
- GRANT SELECT ON employees TO SCOTT;
- ALTER TABLE employees SET UNUSED COLUMN sal;
- SELECT MAX(sal) FROM employees WHERE department_id = 20;
46. Examine the data from the EMP table:
EMP_ID DEPT_ID COMMISSION
1 10 500
2 20 1000
3
10
4
10 600
5
30 800
6
30 200
7
10
8
20 300
The COMMISSION column shows the monthly commission earned by
the employee. Which three tasks would require Subqueries or joins in order to
perform in a single step? (Choose three)
A.
Deleting the records of employees who do not earn
commission.
B.
Increasing the commission of employee 3 by
the average commission earned in department 20.
C.
Finding the number of employees who do NOT earn
commission and are working for department 20.
D.
Inserting into the table a new employee 10
who works for department 20 and earns a commission that is equal to the
commission earned by employee 3.
E.
Creating a table called COMMISSION that has
the same structure and data as the columns EMP_ID and COMMISSIONS of the EMP
table.
F.
Decreasing the commission by 150 for the employees
who are working in department 30 and earning a commission of more then 800.
47. View
the image below and examine the data from the EMP table. Evaluate this
SQL statement:
SELECT * FROM EMP
WHERE commission = (SELECT commission FROM EMP WHERE emp_id = 3); what is the
result when the query is executed?
- ===
- ===
- The query returns no rows.
- The query fails because the outer query is retrieving more than one column.
- The query fails because both the inner and outer queries are retrieving data from the same table.
48. Examine the data in the
EMPLOYEES and DEPARTMENTS tables.
EMPLOYEES LAST_NAME DEPARTMENT_ID
SALARY
Getz 10
3000
Davis 20
1500
King 20
2200
Davis 30
5000
Kochhar 5000
DEPARTMENTS
DEPARTMENT_ID DEPARTMENT_NAME
10 Sales
20 Marketing
30 Accounts
40 Administration
You want to retrieve all employees, whether or not they have
matching departments in the departments table. Which query would you use?
- SELECT last_name, department_name FROM employees , departments(+);
- SELECT last_name, department_name FROM employees JOIN departments (+);
- SELECT last_name, department_name FROM employees(+) e JOIN departments d ON (e.department_id = d.department_id);
- SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
- SELECT last_name, department_name FROM employees(+) , departments ON (e.department_id = d.department_id);
- SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
49. Examine the structure of
the EMPLOYEES table:
EMPLOYEE_ID NUMBER
Primary Key
FIRST_NAME VARCHAR2
(25)
LAST_NAME VARCHAR2
(25)
Which three statements insert a row into the table?
(Choose three.)
- INSERT INTO employees VALUES ( NULL, 'John', 'Smith');
- INSERT INTO employees( first_name, last_name) VALUES( 'John', 'Smith');
- INSERT INTO employees VALUES ( '1000', 'John', NULL);
- INSERT INTO employees (first_name, last_name, employee_id) VALUES ( 1000, 'John', 'Smith');
- INSERT INTO employees (employee_id) VALUES (1000);
- INSERT INTO employees (employee_id, first_name, last_name) VALUES ( 1000, 'John', ‘ ');
50. Evaluate these two SQL statements:
SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER
BY salary DESC; SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER BY 2
DESC;
What is true about them?
- The two statements produce identical results.
- The second statement returns a syntax error.
- There is no need to specify DESC because the results are sorted in descending order by default.
- The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.
51. Examine the structure of
the EMPLOYEES table:
EMPLOYEE_ID NUMBER
Primary Key
FIRST_NAME VARCHAR2
(25)
LAST_NAME VARCHAR2
(25)
HIRE_DATE DATE
Which UPDATE statement is valid?
- UPDATE employees SET first_name = 'John' SET last_name='Smith' WHERE employee_id = 180;
- UPDATE employees SET first_name = 'John', SET last_name ='Smith' WHERE employee_id = 180;
- UPDATE employees SET first_name = 'John' AND last_name ='Smith' WHERE employee_id = 180;
- UPDATE employees SET first_name = 'John', last_name ='Smith' WHERE employee_id = 180;
52. Evaluate the SQL statement DROP TABLE DEPT;
Which four statements are true of the SQL statement? (Choose
four.)
A. You cannot roll back this statement.
- All pending transactions are committed.
- All views based on the DEPT table are deleted.
- All indexes based on the DEPT table are dropped.
- All data in the table is deleted, and the table structure is also deleted.
- All data in the table is deleted, but the structure of the table is retained.
- All synonyms based on the DEPT table are deleted.
53. The user Sue issues this SQL
statement: GRANT SELECT ON sue.EMP TO Alice WITH GRANT OPTION; The user Alice
issues this SQL statement: GRANT SELECT ON sue.EMP TO Rena WITH GRANT OPTION;
The user Rena issues this SQL statement: GRANT SELECT ON sue.EMP TO timber; The
user Sue issues this SQL statement: REVOKE select on sue.EMP FROM Alice; For
which users does the revoke command revoke SELECT privileges on the SUE.EMP
table?
A. Alice only
B. Alice and Rena
C. Alice, Rena, and Timber
D. Sue, Alice, Rena, and Timber
54. The EMPLOYEES table contains these columns:
EMPLOYEE_ID NUMBER
(4)
LAST_NAME VARCHAR2
(25)
JOB_ID VARCHAR2
(10)
You want to search for strings that contain 'SA_' in the
JOB_ID column. Which SQL statement do you use?
- SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA\_%' ESCAPE '\';
- SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_';
- SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_' ESCAPE "\";
- SELECT employee_id, last_name, job_id FROM employees WHERE job_id = '%SA_';
55. Examine the structure of the
EMPLOYEES table:
Column name Data
type Remarks
EMPLOYEE_ID NUMBER
NOT NULL, Primary Key
LAST_NAME VARCHAR2
(30)
FIRST_NAME VARCHAR2
(30)
JOB_ID NUMBER
SAL NUMBER
MGR_ID NUMBER
References EMPLOYEE_ID column DEPARTMENT_ID NUMBER
You need to create an index called NAME_IDX on the first
name and last name fields of the EMPLOYEES table. Which SQL statement would you
use to perform this task?
- CREATE INDEX NAME_IDX (first_name, last_name);
- CREATE INDEX NAME_IDX (first_name AND last_name);
- CREATE INDEX NAME_IDX ON (first_name, last_name);
- CREATE INDEX NAME_IDX ON employees (first_name AND last_name);
- CREATE INDEX NAME_IDX ON employees(first_name, last_name);
- CREATE INDEX NAME_IDX FOR employees(first_name, last_name);
56. The CUSTOMERS table has these columns:
CUSTOMER_ID NUMBER
(4) NOT NULL
CUSTOMER_NAME VARCHAR2
(100) NOT NULL
CUSTOMER_ADDRESS VARCHAR2
(150)
CUSTOMER_PHONE VARCHAR2
(20)
You need to produce output that states "Dear
Customer customer_name”. The customer_name data values come from the
CUSTOMER_NAME column in the CUSTOMERS table. Which statement produces this
output?
- SELECT dear customer, customer_name, FROM customers;
- SELECT "Dear Customer", customer_name || ',' FROM customers;
- SELECT 'Dear Customer ' || customer_name ',' FROM customers;
- SELECT 'Dear Customer ' || customer_name || ',' FROM customers;
- SELECT "Dear Customer " || customer_name || "," FROM customers;
- SELECT 'Dear Customer ' || customer_name || ',' || FROM customers;
57. What is true about
sequences?
- Once created, a sequence belongs to a specific schema.
- Once created, a sequence is linked to a specific table.
- Once created, a sequence is automatically available to all users.
- Only the DBA can control which sequence is used by a certain table.
- Once created, a sequence is automatically used in all INSERT and UPDATE statements.
58. Which statement describes
the ROWID data type?
- binary data up to 4 gigabytes
- character data up to 4 gigabytes
- raw binary data of variable length up to 2 gigabytes
- binary data stored in an external file, up to 4 gigabytes
- a hexadecimal string representing the unique address of a row in its table
59. Which object privileges can be granted on a view?
A. none
B. DELETE, INSERT, SELECT
C. ALTER, DELETE, INSERT, SELECT
D. DELETE, INSERT, SELECT, UPDATE
60. Examine the SQL statement
that creates ORDERS table:
CREATE TABLE orders (SER_NO NUMBER UNIQUE, ORDER_ID
NUMBER, ORDER_DATE DATE NOT NULL, STATUS VARCHAR2 (10) CHECK (status IN
('CREDIT', 'CASH')), PROD_ID NUMBER REFERENCES PRODUCTS (PRODUCT_ID), ORD_TOTAL
NUMBER, PRIMARY KEY (order_id, order_date));
For which columns would an index be automatically created
when you execute the above SQL statement? (Choose two.)
- SER_NO
- ORDER_ID
- STATUS
- PROD_ID
- ORD_TOTAL
- composite index on ORDER_ID and ORDER_DATE
61. What is true of using group functions on columns that
contain NULL values?
- Group functions on columns ignore NULL values.
- Group functions on columns returning dates include NULL values.
- Group functions on columns returning numbers include NULL values.
- Group functions on columns cannot be accurately used on columns that contain NULL values.
- Group functions on columns include NULL values in calculations if you use the keyword INC_NULLS.
62. The STUDENT_GRADES table has these columns:
STUDENT_ID NUMBER
(12)
SEMESTER_END DATE
GPA NUMBER
(4, 3)
Which statement finds the highest grade point average
(GPA) per semester?
- SELECT MAX(gpa) FROM student_grades WHERE gpa IS NOT NULL;
- SELECT (gpa) FROM student_grades GROUP BY semester_end WHERE gpa IS NOT NULL;
- SELECT MAX(gpa) FROM student_grades WHERE gpa IS NOT NULL GROUP BY semester_end;
- SELECT MAX(gpa) GROUP BY semester_end WHERE gpa IS NOT NULL FROM student_grades;
- SELECT MAX(gpa) FROM student_grades GROUP BY semester_end WHERE gpa IS NOT NULL;
63. In which four clauses can a subquery be used? (Choose
four.)
- in the INTO clause of an INSERT statement
- in the FROM clause of a SELECT statement
- in the GROUP BY clause of a SELECT statement
- in the WHERE clause of a SELECT statement
- in the SET clause of an UPDATE statement
- in the VALUES clause of an INSERT statement
64. Examine this statement:
SELECT student_id, GPA FROM student_grades WHERE GPA >
&&value;
You run the statement once, and when prompted you enter a
value of 2.0. A report is produced. What happens when you run the statement a
second time?
- An error is returned.
- You are prompted to enter a new value.
- A report is produced that matches the first report produced.
- You are asked whether you want a new value or if you want to run the report based on the previous value.
65. Which SQL statement returns
a numeric value?
- SELECT ADD_MONTHS(MAX (hire_date), 6) FROM EMP;
- SELECT ROUND(hire_date)FROM EMP;
- SELECT sysdate-hire_date FROM EMP;
- SELECT TO_NUMBER(hire_date + 7)FROM EMP;
66. What are two reasons to create synonyms? (Choose
two.)
- You have too many tables.
- Your tables are too long.
- Your tables have difficult names.
- You want to work on your own tables.
- You want to use another schema's tables.
- You have too many columns in your tables.
67. Examine the data of the EMPLOYEES table.
EMPLOYEES (EMPLOYEE_ID is the primary key.
MGR_ID is the ID of managers and refers to the EMPLOYEE_ID)
EMPLOYEE_ID EMP_NAME DEPT_ID MGR_ID JOB_ID SALARY
101 Smith
20 120 SA_REP
4000
102 Martin
10 105 CLERK
2500
103 Chris
20 120 IT_ADMIN
4200
104 John
30 108 HR_CLERK
2500
105 Diana
30 108 HR_MGR
5000
106 Bryan
40 110 AD_ASST
3000
108 Jennifer
30 110 HR_DIR
6500
110 Bob
40 EX_DIR
8000
120 Ravi
20 110 SA_DIR 6500
Evaluate this SQL statement:
SELECT e.employee_id "Emp_id", e.emp_name
"Employee", e.salary, m.employee_id "Mgr_id", m.emp_name
"Manager" FROM employees e, employees m WHERE e.mgr_id =
m.employee_id AND e.salary > 4000;
What is its output?
A.
Emp_id EMPLOYEE
SALARY Mgr_id Manager
---- --------- ------------- ---------------- -------------
110 Bob 8000 Bob
120 Ravi 6500
110 Ravi
108 Jennifer 6500
110 Jennifer
103 Chris 4200
120 Chris
105 Diana 5000
108 Diana
B.
Emp_id EMPLOYEE SALARY Mgr_id
Manager
------- -------------
----------------- ------------------
120 Ravi
6500
110 Bob
108 Jennifer
6500
110 Bob
103 Chris
4200
120 Ravi
105 Diana
5000
108 Jennifer
C. Emp_id EMPLOYEE SALARY Mgr_id
Manager
------- ---------- --------- -------------
110 Bob 8000
120 Ravi 6500
110 Bob
108 Jennifer 6500
110 Bob
103 Chris 4200
120 Ravi
105 Diana 5000
108 Jennifer
D. Emp_id EMPLOYEE
SALARY Mgr_id Manager
------- ----------
--------- --------------
110 Bob
8000
110 Bob
120 Ravi
6500
120 Ravi
108 Jennifer
6500
108 Jennifer
103 Chris
4200
103 Chris
105 Diana
5000
105 Dina
E. the SQL statement produces an error.
68. What is true about updates through a view?
- You cannot update a view with group functions.
- When you update a view group functions are automatically computed.
- When you update a view only the constraints on the underlying table will be in effect.
- When you update a view the constraints on the views always override the constraints on the underlying tables.
69. You need to write a SQL statement that
returns employee name, salary, department ID, and
maximum salary earned in the department of the employee for all employees who
earn less than the maximum salary in their department.
Which statement accomplishes this task?
A.
SELECT a.emp_name, a.sal, b.dept_id, MAX(sal)
FROM employees a, departments b WHERE a.dept_id = b.dept_id AND a.sal <
MAX(sal) GROUP BY b.dept_id;
- SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) b WHERE a.dept_id = b.dept_id AND a.sal < b.maxsal;
- SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a WHERE a.sal < (SELECT MAX(sal) maxsal FROM employees b GROUP BY dept_id);
- SELECT emp_name, sal, dept_id, maxsal FROM employees, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) WHERE a.sal < maxsal;
Answer: B
70. View the image below and examine the data from the
ORDERS and CUSTOMERS tables. Evaluate this SQL statement:
SELECT cust_id, ord_total FROM orders WHERE ord_total >
ANY(SELECT ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM
customers WHERE city LIKE 'New York'));
What is the result when the above query is executed?
A. **
B. **
C. **
D. **
E.
The query returns no rows.
F.
The query fails because ANY is not a valid operator
with a subquery.
71. Mark for review You need to create a table
named ORDERS that contains four columns: - an ORDER_ID column of number data
type - a CUSTOMER_ID column of number data type - an ORDER_STATUS column that
contains a character data type - a DATE_ORDERED column to contain the date the
order was placed. When a row is inserted into the table, if no value is
provided when the order was placed, today's date should be used instead.
Which statement accomplishes this?
A. CREATE
TABLE orders (order_id NUMBER(10), customer_id NUMBER(8),order_status VARCHAR2
(10),date_ordered DATE = SYSDATE);
B. CREATE TABLE orders (order_id NUMBER(10), customer_id
NUMBER(8),order_status VARCHAR2 (10),date_ordered DATE DEFAULT SYSDATE);
C. CREATE
OR REPLACE TABLE orders (order_id NUMBER(10), customer_id
NUMBER(8),order_status VARCHAR2 (10),date_ordered DATE DEFAULT SYSDATE);
D. CREATE
OR REPLACE TABLE orders (order_id NUMBER(10), customer_id
NUMBER(8),order_status VARCHAR2 (10),date_ordered DATE = SYSDATE);
E. CREATE
TABLE orders (order_id NUMBER(10), customer_id NUMBER(8),order_status NUMBER
(10),date_ordered DATE = SYSDATE);
F. CREATE
TABLE orders (order_id NUMBER(10), customer_id NUMBER(8),order_status NUMBER
(10),date_ordered DATE DEFAULT SYSDATE);
72. Mark for review Evaluate the
SQL statement:
SELECT ROUND (45.953, -1), TRUNC (45.936, 2) FROM dual;
Which values are displayed?
- 46 and 45
- 46 and 45.93
- 50 and 45.93
- 50 and 45.9
- 45 and 45.93
- 45.95 and 45.93
73.
Mark for review. The CUSTOMERS table has these
columns:
CUSTOMER_ID NUMBER
(4) NOT NULL
CUSTOMER_NAME VARCHAR2
(100) NOT NULL
STREET_ADDRESS VARCHAR2
(150)
CITY_ADDRESS VARCHAR2
(50)
STATE_ADDRESS VARCHAR2
(50)
PROVINCE_ADDRESS VARCHAR2 (50)
COUNTRY_ADDRESS VARCHAR2
(50)
POSTAL_CODE VARCHAR2
(12)
CUSTOMER_PHONE VARCHAR2
(20)
A promotional sale is being advertised to the customers
in France. Which WHERE clause identifies customers that are located in France?
- WHERE lower(country_address) = "France"
- WHERE lower(country_address) = 'france'
- WHERE lower(country_address) IS 'France'
- WHERE lower(country_address) = '%France%'
- WHERE lower(country_address) LIKE %France%
74. Mark for review Examine the description of the CUSTOMERS
table:
CUSTOMER_ID NUMBER
(4) NOT NULL
CUSTOMER_NAME VARCHAR2
(100) NOT NULL
STREET_ADDRESS VARCHAR2
(150)
CITY_ADDRESS VARCHAR2
(50)
STATE_ADDRESS VARCHAR2
(50)
PROVINCE_ADDRESS VARCHAR2 (50)
COUNTRY_ADDRESS VARCHAR2
(50)
POSTAL_CODE VARCHAR2
(12)
CUSTOMER_PHONE VARCHAR2
(20)
The CUSTOMER_ID column is the primary key for the table.
Which statement
returns the city address and the number of customers in the cities Los Angeles
or San Francisco?
- SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco');
- SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address;
- SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address, customer_id;
- SELECT city_address, COUNT(customer_id) FROM customers GROUP BY city_address IN ('Los Angeles', 'San Francisco');
75. Mark for review what does
the FORCE option for creating a view do?
- creates a view with constraints
- creates a view even if the underlying parent table has constraints
- creates a view in another schema even if you don't have privileges
- creates a view regardless of whether or not the base tables exist
76. Mark for review The CUSTOMERS table has these
columns:
CUSTOMER_ID NUMBER
(4) NOT NULL
CUSTOMER_NAME VARCHAR2
(100) NOT NULL
STREET_ADDRESS VARCHAR2
(150)
CITY_ADDRESS VARCHAR2
(50)
STATE_ADDRESS VARCHAR2
(50)
PROVINCE_ADDRESS VARCHAR2 (50)
COUNTRY_ADDRESS VARCHAR2
(50)
POSTAL_CODE VARCHAR2
(12)
CUSTOMER_PHONE VARCHAR2
(20)
The CUSTOMER_ID column is the primary key for the table. You
need to determine how dispersed your customer base is. Which expression finds
the number of different countries represented in the CUSTOMERS table?
A.
COUNT(UPPER(country_address))
- COUNT(DIFF(UPPER(country_address)))
- COUNT(UNIQUE(UPPER(country_address)))
- COUNT DISTINCT UPPER(country_address)
- COUNT(DISTINCT (UPPER(country_address)))
77. Mark for review a data
manipulation language statement _____.
- completes a transaction on a table
- modifies the structure and data in a table
- modifies the data but not the structure of a table
- modifies the structure but not the data of a table
78. Mark for review which two
tasks can you perform using only the TO_CHAR function? (Choose two.)
- convert 10 to 'TEN'
- convert '10' to 10
- convert 10 to '10'
- convert 'TEN' to 10
- convert a date to a character expression
- convert a character expression to a date
79. Mark for review The DBA issues this SQL
command: CREATE USER Scott IDENTIFIED by tiger; what
privileges do the user Scott has at this point?
- no privileges
- only the SELECT privilege
- only the CONNECT privilege
- all the privileges of a default user
80. Mark for review View the
image below and examine the data in the EMPLOYEES table.
Examine the subquery:
SELECT last_name FROM employees WHERE salary IN (SELECT MAX
(salary) FROM employees GROUP BY department_id);
Which statement is true?
A. The SELECT statement is syntactically accurate.
B. The
SELECT statement does not work because there is no HAVING clause.
C. The
SELECT statement does not work because the column specified in the GROUP BY
clause is not in the SELECT list.
D. The
SELECT statement does not work because the GROUP BY clause should be in the
main query and not in the subquery.
81. Mark for review you need to
produce a report for mailing labels for all customers. The mailing label must have only the customer name and address.
The CUSTOMERS table has these columns:
CUST_ID NUMBER
(4) NOT NULL
CUST_NAME VARCHAR2
(100) NOT NULL
CUST_ADDRESS VARCHAR2
(150)
CUST_PHONE VARCHAR2
(20)
Which SELECT statement accomplishes this task?
- SELECT *FROM customers;
- SELECT name, address FROM customers;
- SELECT id, name, address, phone FROM customers;
- SELECT cust_name, cust_address FROM customers;
- SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
82. Mark for review Examine the
statement:
GRANT select, insert, update ON student_grades TO manager
WITH GRANT OPTION; which two are true? (Choose two.)
- MANAGER must be a role.
- It allows the MANAGER to pass the specified privileges on to other users.
- It allows the MANAGER to create tables that refer to the STUDENT_GRADES table.
- It allows the MANAGER to apply all DML statements on the STUDENT_GRADES table.
- It allows the MANAGER the ability to select from, insert into, and update the STUDENT_GRADES table.
- It allows the MANAGER the ability to select from, delete from, and update the STUDENT_GRADES table.
83. Mark for review which best describes an
inline view?
- a schema object
- a subquery that can contain an ORDER BY clause
- another name for a view that contains group functions
- a subquery that is part of the FROM clause of another query
84. Mark for review. Examine the structure of the
EMPLOYEES and DEPARTMENTS tables:
EMPLOYEES
EMPLOYEE_ID NUMBER
DEPARTMENT_ID NUMBER
MANAGER_ID NUMBER
LAST_NAME VARCHAR2
(25)
DEPARTMENTS
DEPARTMENT_ID NUMBER
MANAGER_ID NUMBER
DEPARTMENT_NAME VARCHAR2
(35)
LOCATION_ID NUMBER
You want to create a report displaying employee last names,
department names, and locations. Which query should you use to create an
Equijoin?
A. SELECT
last_name, department_name, location_id FROM employees , departments ;
B. SELECT
employees.last_name, departments.department_name, departments.location_id FROM
employees e, departments D WHERE e.department_id =d.department_id;
C. SELECT
e.last_name, d.DEPARTMENT_NAME, d.location_id FROM employees e, departments D
WHERE manager_id =manager_id;
D. SELECT e.last_name, d.DEPARTMENT_NAME, d.location_id FROM
employees e, departments D WHERE e.department_id =d.department_id;
85. Mark for review The PRODUCTS table has these
columns:
PRODUCT_ID NUMBER
(4)
PRODUCT_NAME VARCHAR2
(45)
PRICE NUMBER
(8, 2)
Evaluate this SQL statement:
SELECT * FROM PRODUCTS ORDER BY price, product_name;
What is true about the SQL statement?
- The results are not sorted.
- The results are sorted numerically.
- The results are sorted alphabetically.
- The results are sorted numerically and then alphabetically.
86. Examine the data in the
EMPLOYEES table:
LAST_NAME DEPARTMENT_ID SALARY
Getz 10
3000
Davis 20
1500
King 20
2200
Davis 30
5000
Which three Subqueries work? (Choose three)
- SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
- SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
- SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
- SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
- SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
- SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));
87. Mark for review. In which
two cases would you use an outer join? (Choose two.)
- The tables being joined have NOT NULL columns.
- The tables being joined have only matched data.
- The columns being joined have NULL values.
- The tables being joined have only unmatched data.
- The tables being joined have both matched and unmatched data.
- Only when the tables have a primary key/foreign key relationship.
88. Mark for review. In which
case would you use a FULL OUTER JOIN?
- Both tables have NULL values.
- You want all unmatched data from one table.
- You want all matched data from both tables.
- You want all unmatched data from both tables.
- One of the tables has more data than the other.
- You want all matched and unmatched data from only one table.
89. Mark for review. Which constraint can be
defined only at the column level?
A. UNIQUE
B. NOT NULL
C. CHECK
D. PRIMARY KEY
E. FOREIGN KEY
90.
Mark for review. Examine the structure of the EMPLOYEES table:
EMPLOYEE_ID NUMBER
Primary Key
FIRST_NAME VARCHAR2
(25)
LAST_NAME VARCHAR2
(25)
HIRE_DATE DATE
You issue these statements:
CREATE table new_emp (employee_id NUMBER, name VARCHAR2 (30));
INSERT INTO new_emp SELECT employee_id , last_name from
employees;
Savepoint s1;
UPDATE new_emp set name = UPPER (name);
Savepoint s2;
Delete from new_emp;
Rollback to s2;
Delete from new_emp where employee_id =180;
UPDATE new_emp set name = 'James';
Rollback to s2;
UPDATE new_emp set name = 'James' WHERE employee_id =180;
Rollback;
At the end of this transaction, what is true?
- You have no rows in the table.
- You have an employee with the name of James.
- You cannot roll back to the same Savepoint more than once.
- Your last update fails to update any rows because employee ID 180 was already deleted.
91. Mark for review Which SQL statement
generates the alias Annual Salary for the calculated
column SALARY*12?
- SELECT ename, salary*12 'Annual Salary' FROM employees;
- SELECT ename, salary*12 "Annual Salary" FROM employees;
- SELECT ename, salary*12 AS Annual Salary FROM employees;
- SELECT ename, salary*12 AS INITCAP("ANNUAL SALARY") FROM employees
92. Mark for review View the
image below and examine the data in the EMPLOYEES and DEPARTMENTS tables.
On the EMPLOYEES table,
EMPLOYEE_ID is the primary key.
MGR_ID is the ID of managers and refers to the EMPLOYEE_ID.
On the DEPARTMENTS table,
DEPARTMENT_ID is the primary key.
Evaluate this UPDATE statement:
UPDATE employees SET mgr_id = (SELECT mgr_id FROM employees
WHERE dept_id = (SELECT department_id FROM departments WHERE department_name =
'Administration') ), Salary = (SELECT salary FROM employees WHERE emp_name =
'Smith') WHERE job_id = 'IT_ADMIN';
What happens when the statement is executed?
- The statement executes successfully, leaves the manager ID as the existing value, and changes the salary to 4000 for the employees with ID 103 and 105.
- The statement executes successfully, changes the manager ID to NULL, and changes the salary to 4000 for the employees with ID 103 and 105.
- The statement executes successfully, changes the manager ID to NULL, and changes the salary to 3000 for the employees with ID 103 and 105.
- The statement fails because there is more than one row matching the employee name Smith.
- The statement fails because there is more than one row matching the IT_ADMIN job ID in the EMPLOYEES table.
- The statement fails because there is no 'Administration' department in the DEPARTMENTS table
93. Mark for review. Examine the structure of the EMPLOYEES
table:
EMPLOYEE_ID
NUMBER NOT NULL
EMP_NAME VARCHAR2 (30)
JOB_ID VARCHAR2 (20)
SAL NUMBER
MGR_ID NUMBER
DEPARTMENT_ID
NUMBER
You want to create a SQL script file that contains an INSERT
statement. When the script is run, the INSERT statement should insert a row
with the specified values into the EMPLOYEES table. The INSERT statement should
pass values to the table columns as specified below:
EMPLOYEE_ID: Next value from the sequence
EMP_ID_SEQEMP_NAME and JOB_ID: As specified by the user
during run time, through substitution variables
SAL: 2000 MGR_ID: No value
DEPARTMENT_ID: Supplied by the user during run time through
substitution variable.
The INSERT statement should fail if the user supplies a
value other than 20 or 50.
Which INSERT statement meets the above requirements?
- INSERT INTO employees VALUES (emp_id_seq. NEXTVAL, '&ename', '&job_Id', 2000, NULL, &did);
- INSERT INTO employees VALUES (emp_id_seq. NEXTVAL, '&ename', '&job_Id', 2000, NULL, &did IN (20,50));
- INSERT INTO (SELECT * FROM employees WHERE department_id IN (20,50)) VALUES (emp_id_seq. NEXTVAL, '&ename', '&job_id', 2000, NULL, &did);
- INSERT INTO (SELECT * FROM employees WHERE department_id IN (20,50) WITH CHECK OPTION)VALUES (emp_id_seq. NEXTVAL, '&ename', '&job_id', 2000, NULL, &did);
- NSERT INTO (SELECT * FROM employees WHERE (department_id = 20 AND department_id = 50) WITH CHECK OPTION )VALUES (emp_id_seq. NEXTVAL, '&ename', '&job_id', 2000, NULL, &did);
94. Mark for review. The user
Alice wants to grant all users query privileges on her DEPT table. Which SQL
statement accomplishes this?
- GRANT select ON dept TO ALL_USERS;
- GRANT select ON dept TO ALL;
- GRANT QUERY ON dept TO ALL_USERS
- GRANT select ON dept TO PUBLIC;
95. Mark for review. Which view should a user
query to display the columns associated with the constraints on a table owned
by the user?
A. USER_CONSTRAINTS
B. USER_OBJECTS
C. ALL_CONSTRAINTS
D. USER_CONS_COLUMNS
E. USER_COLUMNS
96. Mark for review. Which two
statements are true about WHERE and HAVING clauses? (Choose two.)
- A WHERE clause can be used to restrict both rows and groups.
- A WHERE clause can be used to restrict rows only.
- A HAVING clause can be used to restrict both rows and groups.
- A HAVING clause can be used to restrict groups only.
- A WHERE clause CANNOT be used in a query if the query uses a HAVING clause.
- A HAVING clause CANNOT be used in Subqueries.
97.
Mark for review. The EMP table contains these columns:
LAST_NAME VARCHAR2 (25)
SALARY NUMBER (6, 2)
DEPARTMENT_ID
NUMBER (6)
You need
to display the employees who have not been assigned to any department. You
write the SELECT statement:
SELECT
LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL;
What is
true about this SQL statement?
- The SQL statement displays the desired results.
- The column in the WHERE clause should be changed to display the desired results.
- The operator in the WHERE clause should be changed to display the desired results.
- The WHERE clause should be changed to use an outer join to display the desired results.
98. Mark for review Examine
these statements:
CREATE
ROLE registrar;
GRANT
UPDATE ON student_grades TO registrar;
GRANT
registrar to user1, user2, user3;
What does this set of SQL statements do?
- The set of statements contains an error and does not work.
- It creates a role called REGISTRAR, adds the MODIFY privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
- It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
- It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and creates three users with the role.
- It creates a role called REGISTRAR, adds the UPDATE privilege on three users, and gives the REGISTRAR role to the STUDENT_GRADES object.
- It creates a role called STUDENT_GRADES, adds the UPDATE privilege on three users, and gives the UPDATE role to the registrar.
99. Mark for review. You need to design a student
registration database that contains several tables storing academic
information.
The
STUDENTS table stores information about a student. The STUDENT_GRADES table
stores information about the student's grades. Both of the tables have a column
named STUDENT_ID. The STUDENT_ID column in the STUDENTS table is a primary key.
You need
to create a foreign key on the STUDENT_ID column of the STUDENT_GRADES table
that points to the STUDENT_ID column of the STUDENTS table. Which statement
creates the foreign key?
A. CREATE
TABLE student_grades (student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3),
CONSTRAINT student_id_fk REFERENCES (student_id) FOREIGN KEY
students(student_id));
- CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), student_id_fk FOREIGN KEY (student_id) REFERENCES students(student_id));
- CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT FOREIGN KEY (student_id) REFERENCES students(student_id));
- CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT student_id_fk FOREIGN KEY (student_id) REFERENCES students(student_id));
100. Mark for review. Evaluate
the SQL statement:
TRUNCATE TABLE DEPT;
Which three are true about the SQL statement? (Choose
three.)
- It releases the storage space used by the table.
- It does not release the storage space used by the table.
- You can roll back the deletion of rows after the statement executes.
- You can NOT rollback the deletion of rows after the statement executes.
- An attempt to use DESCRIBE on the DEPT table after the TRUNCATE statement executes will display an error.
- You must be the owner of the table or have DELETE ANY TABLE system privileges to truncate the DEPT table
101. Evaluate the SQL statement
DROP TABLE DEPT: Which four statements are true of the SQL statement? (Choose four)
- You cannot roll back this statement.
- All pending transactions are committed.
- All views based on the DEPT table are deleted.
- All indexes based on the DEPT table are dropped.
- All data in the table is deleted, and the table structure is also deleted.
- All data in the table is deleted, but the structure of the table is retained.
- All synonyms based on the DEPT table are deleted.
102. Mark for review. You need to create a view
EMP_VU. The view should allow the users to manipulate the records of only the
employees that are working for departments 10 or 20. Which SQL statement would
you use to create the view EMP_VU?
A. CREATE
VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);
B. CREATE
VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH READ
ONLY;
- CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH CHECK OPTION;
- CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);]
- CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) NO UPDATE;
103. Mark for review View the image below and
examine the data from the EMP table.
The COMMISSION column shows the monthly commission earned by
the employee. Which two tasks would require Subqueries or joins in order to be
performed in a single step? (Choose two.) (Select all that apply)
- listing the employees who earn the same amount of commission as employee 3
- finding the total commission earned by the employees in department 10
- finding the number of employees who earn a commission that is higher than the average commission of the company
- listing the departments whose average commission is more than 600 E. listing the employees who do not earn commission and who are working for department 20 in descending order of the employee ID
- listing the employees whose annual commission is more than 6000
104. Mark for review. Which two
statements are true about constraints? (Choose two.)
- The UNIQUE constraint does not permit a null value for the column.
- A UNIQUE index gets created for columns with PRIMARY KEY and UNIQUE constraints.
- The PRIMARY KEY and FOREIGN KEY constraints create a UNIQUE index.
- The NOT NULL constraint ensures that null values are not permitted for the column.
105. Mark for review Examine the statement:
Create synonym EMP for hr.employees;
What happens when you issue the statement?
A.
An error is generated.
- You will have two identical tables in the HR schema with different names.
- You create a table called employees in the HR schema based on your EMP table.
- You create an alternative name for the employees table in the HR schema in your own schema
106. You need to change the definition of an
existing table. The COMMERCIALS table needs its DESCRIPTION column changed to
hold varying length characters up to 2000 bytes. The column can currently hold
1000 bytes per value. The table contains 20000 rows. Which statement is valid?
- ALTER TABLE commercials MODIFY (description CHAR2(2000));
- B. ALTER TABLE commercials CHANGE (description CHAR2(2000));
- C. ALTER TABLE commercials CHANGE (description VARCHAR2(2000));
- D. ALTER TABLE commercials MODIFY (description VARCHAR2(2000));
- E. You cannot increase the size of a column if the table has rows.
107. Mark for review Which SQL
statement accepts user input for the columns to be displayed, the table name,
and the WHERE condition?
- SELECT &1, "&2"FROM &3 WHERE last_name = '&4';
- SELECT &1, '&2' FROM &3 WHERE '&last_name = '&4'';
- SELECT &1, &2 FROM &3 WHERE last_name = '&4';
- SELECT &1, '&2' FROM EMP WHERE last_name = '&4';
108. Mark for review The
STUDENT_GRADES table has these columns:
STUDENT_ID NUMBER
(12)
SEMESTER_END DATE
GPA NUMBER
(4, 3)
The registrar has requested a report listing the
students' grade point averages (GPA), sorted from highest grade point average
to lowest within each semester, starting from the earliest date. Which
statement accomplishes this?
- SELECT student_id, semester_end, gpa FROM student_grades ORDER BY semester_end DESC, gpa DESC;
- SELECT student_id, semester_end, gpa FROM student_grades ORDER BY semester_end ASC, gpa ASC;
- SELECT student_id, semester_end, gpa FROM student_grades ORDER BY semester_end, gpa DESC;
- SELECT student_id, semester_end, gpa FROM student_grades ORDER BY gpa DESC, semester_end DESC;
- SELECT student_id, semester_end, gpa FROM student_grades ORDER BY gpa DESC, semester_end ASC;
109. Mark for review Examine the structure of the
EMPLOYEES and NEW_EMPLOYEES tables:
EMPLOYEES
EMPLOYEE_ID NUMBER
Primary Key
FIRST_NAME VARCHAR2
(25)
LAST_NAME VARCHAR2
(25)
HIRE_DATE DATE
NEW_EMPLOYEES
EMPLOYEE_ID NUMBER
Primary Key
NAME VARCHAR2
(60)
Which DELETE statement is valid?
- DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);
- DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_employees);
- DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name ='Carrey');
- DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE last_name ='Carrey');
110. Mark for review. Which
three are true? (Choose three.)
- A MERGE statement is used to merge the data of one table with data from another.
- A MERGE statement replaces the data of one table with that of another.
- A MERGE statement can be used to insert new rows into a table.
- A MERGE statement can be used to update existing rows in a table.
111. Mark for review. Which is a valid CREATE
TABLE statement?
- CREATE TABLE EMP9$# AS (emp_id number(2));
- CREATE TABLE EMP*123 AS (emp_id number(2));
- CREATE TABLE PACKAGE AS (pack_id number(2));
- CREATE TABLE 1EMP_TEST AS (emp_id number(2));
112. Mark for review A SELECT statement can be
used to perform these three functions: - Choose rows from a table. - Choose
columns from a table. - Bring together data that is stored in different tables
by creating a link between them. Which set of keywords describes these
capabilities?
- difference, projection, join
- selection, projection, join
- selection, intersection, join
- intersection, projection, join
- difference, projection, product
113. Evaluate this SQL statement:
SELECT e.EMPLOYEE_ID, e.LAST_NAME, e.DEPARTMENT_ID,
d.DEPARTMENT_NAME FROM EMP e, DEPARTMENT d WHERE e.DEPARTMENT_ID =
d.DEPARTMENT_ID;
In the statement, which capabilities of a SELECT statement are performed?
- Selection, projection, join
- Difference, projection, join
- Selection, intersection, join
- Intersection, projection, join
- Difference, projection, product
114. Mark for review. Which four
are types of functions available in SQL? (Choose 4)
A. string
B. character
C. integer
D. calendar
E. numeric
F. translation
G. date
H. conversion
115. Mark for review View the image below and
examine the data in the EMPLOYEES and DEPARTMENTS tables.
You want to retrieve all employees' last names, along with
their managers' last names and their department names. Which query would you
use?
A. SELECT
last_name, manager_id, department_name FROM employees e FULL OUTER JOIN
departments d ON (e.department_id = d.department_id);
- SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
- C. SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
- D. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
- E. SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
- F. SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;
116. Mark for review Examine the
structure of the EMPLOYEES table:
EMPLOYEE_ID NUMBER
NOT NULL, Primary Key
EMP_NAME VARCHAR2
(30)
JOB_ID NUMBER
SAL NUMBER
MGR_ID NUMBER
References EMPLOYEE_ID column
DEPARTMENT_ID NUMBER
Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table
You created a sequence called EMP_ID_SEQ in order to populate
sequential values for the EMPLOYEE_ID column of the EMPLOYEES table.
Which two statements regarding the EMP_ID_SEQ sequence are
true? (Choose two.)
- You cannot use the EMP_ID_SEQ sequence to populate the JOB_ID column.
- The EMP_ID_SEQ sequence is invalidated when you modify the EMPLOYEE_ID column.
- The EMP_ID_SEQ sequence is not affected by modifications to the EMPLOYEES table.
- Any other column of NUMBER data type in your schema can use the EMP_ID_SEQ sequence.
- The EMP_ID_SEQ sequence is dropped automatically when you drop the EMPLOYEES table.
- The EMP_ID_SEQ sequence is dropped automatically when you drop the EMPLOYEE_ID column.
117. Mark for review. Which two
are true about aggregate functions? (Choose two.)
- You can use aggregate functions in any clause of a SELECT statement.
- You can use aggregate functions only in the column list of the SELECT clause and in the WHERE clause of a SELECT statement.
- You can mix single row columns with aggregate functions in the column list of a SELECT statement by grouping on the single row columns.
- You can pass column names, expressions, constants, or functions as parameters to an aggregate function.
- You can use aggregate functions on a table, only by grouping the whole table as one single group.
- You cannot group the rows of a table by more than one column while using aggregate functions.
118. Mark for review Examine the structure of the
STUDENTS table:
STUDENT_ID NUMBER
NOT NULL, Primary Key
STUDENT_NAME VARCHAR2
(30)
COURSE_ID VARCHAR2
(10) NOT NULL
MARKS NUMBER
START_DATE DATE
FINISH_DATE DATE
You need to create a report of the 10 students who achieved
the highest ranking in the course INT_SQL and who completed the course in the
year 1999.
Which SQL statement accomplishes this task?
- SELECT student_id, marks, ROWNUM "Rank" FROM students WHERE ROWNUM <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL'ORDER BY marks DESC;
- SELECT student_id, marks, ROWID "Rank" FROM students WHERE ROWID <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99'AND course_id = 'INT_SQL'ORDER BY marks;
- SELECT student_id, marks, ROWNUM "Rank" FROM (SELECT student_id, marks FROM students WHERE ROWNUM <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL' ORDER BY marks DESC);
- SELECT student_id, marks, ROWNUM "Rank" FROM (SELECT student_id, marks FROM students WHERE finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL' ORDER BY marks DESC)WHERE ROWNUM <= 10 ;
- SELECT student_id, marks, ROWNUM "Rank" FROM (SELECT student_id, marks FROM students ORDER BY marks) WHERE ROWNUM <= 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL';
119. What is necessary for your query on an existing view to
execute successfully?
- The underlying tables must have data.
- You need SELECT privileges on the view.
- The underlying tables must be in the same schema.
- You need SELECT privileges only on the underlying tables.
120. Examine the description of
the EMPLOYEES table:
EMP_ID NUMBER (4) NOT NULL
LAST_NAME VARCHAR2 (30) NOT NULL
FIRST_NAME
VARCHAR2 (30)
DEPT_ID NUMBER (2)
JOB_CAT VARCHAR2 (30)
SALARY NUMBER (8, 2)
Which statement shows the maximum salary paid in each job
category of each department?
- SELECT dept_id, job_cat, MAX (salary) FROM employees WHERE salary > MAX (salary);
- SELECT dept_id, job_cat, MAX (salary) FROM employees GROUP BY dept_id, job_cat
- SELECT dept_id, job_cat, MAX(salary) FROM employees;
- SELECT dept_id, job_cat, MAX (salary) FROM employees GROUP BY dept_id;
- SELECT dept_id, job_cat, MAX (salary) FROM employees GROUP BY dept_id, job_cat, salary;
121. Which SELECT statement
will get the result 'elloworld' from the string 'HelloWorld'?
- SELECT SUBSTR ('HelloWorld',1) FROM dual;
- SELECT INITCAP(TRIM('HellowWorld', 1,1) FROM dual
- SELECT LOWER (SUBSTR ('HellowWorld', 2,1) FROM dual
- SELECT LOWER (SUBSTR('HellowWorld', 2,1) FROM dual
- SELECT LOWER (TRIM ('H' FROM 'Hello World')) FROM dual
122. Management has asked you
to calculate the value 12* salary* commission_pct for all the employees
in the EMP table. The EMP table contains these columns:
LAST NAME VARCHAR2 (35) NOT NULL
SALARY NUMBER (9, 2) NOT NULL
COMMISSION_PCT
NUMBER (4, 2)
Which statement ensures that a value is displayed in the
calculated column for all employees?
- SELECT last_name, 12 * salary* commission_pct FROM emp;
- SELECT last_name, 12 * salary* (commission_pct,0) FROM emp;
- SELECT last_name, 12 * salary* (nvl(commission_pct,0) FROM emp;
- SELECT last_name, 12 * salary* (decode(commission_pct,0)) FROM emp;
123. From SQL*Plus, you issue this SELECT statement:
SELECT * FROM orders;
You use this statement to retrieve data from a database
table for _______________. (Choose
all that apply)
A. updating
B. viewing
C. deleting
D. inserting
E. truncating
124.
Which four statements correctly describe functions that are available in SQL?
(Choose four)
- INSTR returns the numeric position of a named character
- NVL 2 returns the first non-null expression in the expression list.
- TRUNCATE rounds the column, expression, or value to n decimal places
- DECODE translates an expression after comparing it to each search value
- TRIM trims the leading or trailing characters (or both) from a character string.
- NVL compares two expressions and returns null if they are equal, or the first expression if they are not equal.
- NULLIF compares two expressions and returns null if they are equal, or the first expression if they are not equal.
125. The EMPLOYEES table has these columns:
LAST_NAME VARCHAR2
(35)
SALARY NUMBER
(8, 2)
COMMISSION_PCT NUMBER
(5, 2)
You want to display the name and annual salary multiplied by
the commission_pct for all employees. For records that have a NULL
commission_pct, a zero must be displayed against the calculated column. Which
SQL statement displays the desired results?
- SELECT last_name, (salary*12)* commission_Pct FROM EMPLOYEES;
- SELECT last_name, (salary*12)* IFNULL(commission_pct,0) FROM EMPLOYEES;
- SELECT last_name, (salary*12)* NVL2(commission_pct,0) FROM EMPLOYEES;
- SELECT last_name, (salary*12)* NVL(commission_pct,0) FROM EMPLOYEES;
126. Which two statements is
true regarding the ORDER BY clause? (Choose two)
- The sort is in ascending order by default
- The sort is in descending order by default
- The ORDER BY clause must precede the WHERE clause.
- The ORDER BY clause is executed on the client side
- The ORDER BY clause comes last in the SELECT statement
- The ORDER BY clause is executed first in the query execution.
127. Click the Exhibit button and examine the data from the
ORDERS and CUSTOMERS tables. ORDERS
ORD_ID ORD_DATE CUST_ID ORD_TOTAL
100 12.JAN.2000
15 10000
101 09.MAR.2000
40 8000
102 09.MAR.2000
35 12500
103 15.MAR.2000
15 12000
104 25.JUN.2000
15 6000
105 18.JUL.2000
20 5000
106 18.JUL.2000
35 7000
107 21.JUL.2000
20 6500
108 04.AUG.2000
10 8000
CUSTOMERS
CUST_ID CUST_NAME
CITY
10 Smith
Los Angeles
15 Bob
San Francisco
20 Martin
Chicago
25 Mary
New York
30 Rina
Chicago
35 Smith
New York
40 Linda
New York
Which SQL statement retrieves the order ID, customer ID,
and order total for the orders that are placed on the same day that Martin
paced his orders?
A.
SELECT ord_id, cust_id, ord_total FROM orders,
customers WHERE cust_name='Martin' AND ord_date IN ('18-JUL-2000';
21-JUL-2000');
B.
SELECT ord_id, cust_id, ord_total FROM
orders WHERE ord_date IN (SELECT ord_date FROM orders WHERE cust_id=(SELECT
cust_id FROM customers WHERE cust_name= 'Martin'));
C.
SELECT ord_id, cust_id, ord_total FROM orders WHERE
ord_date IN (SELECT ord_date FROM orders, customers WHERE cst_name='Martin');
D. SELECT
ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM
customers WHERE cust name = 'Martin')
128. Evaluate the SQL statement:
SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees
a, (SELECT dept_id, MAX (sal) maxsal 4 FROM employees GROUP BY dept_id) b WHERE
a.dept_id = b.dept_id AND a.sal
What is the result of the statement?
- The statement produces an error at line1.
- The statement produces an error at line3.
- The statement produces an error at line6.
- The statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all departments that pay less salary than the maximum salary aid in the company.
- The statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all employees who earn less than the maximum salary in their department.
129. Click the Exhibit button
and examine the data in the EMPLOYEES and DEPARTMENTS tables.
EMPLOYEES
EMP_ID EMP_NAME DEPT_ID MGR_ID JOB_ID SALARY
101 Smith 20 120
SA_REP 4000
102 Martin 10 105
CLERK 2500
103 Chris 20 120
IT ADMIN 4200
104 John 30 108
HR_CLERK 2500
105 Diana 30 108
IT_ADMIN 5000
106 Smith 40 110
AD_ASST 3000
108 Jennifer 30 110
HR_DIR 6500
110 Bob 40 EX_DIR
8000
120 Ravi 20 110
SI_DIR 6500
DEPARTMENTS
DEPARTMENT_ID DEPARTMENT NAME
10 Admin
20 Education
30 IT
40 Human Resources
Also examine the SQL statements that create the EMPLOYEES
and DEPARTMENTS tables:
CREATE TABLE departments (department_id NUMBER PRIMARY KEY,
department_name VARCHAR2 (30));
CREATE TABLE employees (EMPLOEE_ID NUMBER PRIMARY KEY,
EMP_NAME VARCHAR2 (20), DEPT_ID NUMBER REFERENCES departments (department_id)
MGR_ID NUMBER REFERENCES employees (employee id), JOB_ID VARCHAR2 (15). SALARY
NUMBER);
On the EMPLOYEES table, EMPLOYEE_ID is the primary key
MGR_ID is the ID of mangers and refers to the EMPLOYEE_ID DEPT_ID is foreign
key to DEPARTMENT_ID column of the DEPARTMENTS table
On the DEPARTMENTS table, DEPARTMENT_ID is the primary key.
Examine this DELETE statement: DELETE FROM departments WHERE department id=40;
What happens when you execute the DELETE statement?
- Only the row with department ID 40 is deleted in the DEPARTMENTS table.
- The statement fails because there are child records in the EMPLOYEES table with department ID 40.
- The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 110 and 106 are deleted from the EMPLOYEES table.
- The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 106 and 110 and the employees working under employee 110 are deleted from the EMPLOYEES table.
- The row with department ID 40 is deleted in the DEPARTMENTS table. Also all the rows in the EMPLOYEES table are deleted.
- The statement fails because there are no columns specified in the DELETE clause of the DELETE statement.
130. Mary has a view called EMP_DEPT_LOC_VU that was
created based on the EMPLOYEES, DEPARTMENTS, and LOCATIONS tables. She granted
SELECT privilege to Scott on this view. Which option enables Scott to eliminate
the need to qualify the view with the name MARY.EMP_DEPT_LOC_VU each time the
view is referenced?
- Scott can create a synonym for the EMP_DEPT_LOC_VU by using the command CREATE PRIVATE SYNONYM EDL_VU FOR mary.EMP DEPT_LOC_VU; then he can prefix the columns with this synonym
- Scott can create a synonym for the EMP_DEPT_LOC_VU by using the command CREATE SYNONYM EDL_VU FOR mary.EMP DEPT_LOC_VU; then he can prefix the columns with this synonym.
- Scott can create a synonym for the EMP_DEPT_LOC_VU by using the command CREATE LOCAL SYNONYM EDL_VU FOR mary.emp dept_LOC_uv; then he can prefix the columns with the synonym.
- Scott can create a synonym for the EMP_DEPT_LOC_VU by using the command CRETE LOCAL SYNONYM EDL_VU ON Mary(EMP_DEPT_LOC_VU); then he can prefix the columns with this synonym
- Scott cannot create a synonym because synonyms can be created only for tables.
- Scott cannot create any synonym for Mary's view. Mary should create a private synonym for the view and grant SELECT privilege on that synonym to Scott.
131. Which SQL statement
defines a FOREIGN KEY constraint on the DEPT NO column of the EMP table?
- CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk FOREIGN KEY deptno REFERENCES dept deptno);
- CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));
- CRETE TABLE EM (empno NUMBER(4), ename VARCHAR2(35) deptno NUMBER (7,2) NOT NULL, CONSTRAINT em_deptno_fk REFERENCES dept (deptno) FOREIGN KEY (deptno));
- CREATE TABLE EMP (empno NUMBER (4), ename VARCHAR2(35), deptno NUMBER(7,2) FOREIGN KEY CONSTRAINT emp deptno fk REFERENCES dept (deptno));
132. Evaluate the set of SQL statements:
CREATE TABLE dept (dept_id NUMBER (2) dname VARCHAR2 (14),
Loc VARCHAR2 (13)); ROLLBACK;
DESCRIBE DEPT
What is true about the set?
- The DESCRIBE DEPT statement displays the structure of the DEPT table
- The ROLLBACK statement frees the storage space occupied by the DEPT table.
- The DESCRIBE DEPT statement returns an error ORA-04043: object DEPT does not exist
- The DESCRIBE DEPT statement displays the structure of the DEPT table only if there is a COMMIT statement introduced before the ROLLBACK statement.
133. Examine the structure of
the EMPLOYEES and DEPARTMENTS tables:
EMPLOYEES
EMPLOYEE_ID
NUMBER NOT NULL, PRIMARY KEY
EMP_NAME VARCHAR2 (30)
JOB_ID VARCHAR2
(20)
SALARY NUMBER
MGR_ID NUMBER References employee ID
column
DEPARTMENT_ID
NUMBER Foreign key to
DEPARTMENT_ID column of the DEPARTMENT table
DEPARTMENTS
DEPARTMENT_ID
NUMBER NOT NULL, Primary key
DEPARTMENT_NAME
VARCHAR2 (30)
MGR_ID NUMBER References MGR_ID column of
the EMPLOYEES table
Evaluate
this SQL statement;
SELECT
employee_id, e.department_id, department_name, salary FROM employees e,
departments d WHERE e. department_id=d.department_id;
Which SQL statement is equivalent to the above SQL statement?
- SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);
- SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments d ON e.department_id=d.department_id;
- SELECT employee_id, department_id, department_name, salary FROM employees e JOIN departments d ON e.department_id=d.department_id;
- SELECT employee_id, department_id, department_name, salary FROM employees JOIN departments USING (e.department_id, d.department_id);
134. Which SQL statement generates the alias
Annual Salary for the calculated column SALARY*12?
- SELECT ename, salary*12'Annual Salary' FROM employees;
- SELECT ename, salary* 12 "Annual Salary" FROM employees
- SELECT ename, salary* 12 AS Annual Salary FROM employees;
- SELECT ename, salary* 12 AS INITCAP("ANNUAL SALARY") FROM employees
135. In which scenario would an index be most useful?
- The indexed column is declared as NOT NULL.
- The indexed columns are used in the FROM clause
- The indexed columns are part of an expression
- The indexed column contains a wide range of values.
136. Which two are attributes of /SQL*Plus?
(Choose two)
- /SQL*Plus commands cannot be abbreviated.
- /SQL*Plus commands are accesses from a browser.
- /SQL*Plus commands are used to manipulate data in tables.
- /SQL*Plus commands manipulate table definitions in the database.
- /SQL*Plus is the Oracle proprietary interface for executing SQL statements.
Answer: B, E
137. Which three statements
about Subqueries are true? (Choose three).
- A single row subquery can retrieve only one column and one row
- A single row subquery can retrieve only one row but many columns
- A multiple row subquery can retrieve multiple rows and multiple columns
- A multiple row subquery can be compared using the ">" operator
- A single row subquery can use the IN operator
- A multiple row subquery can use the "=" operator
138. When should you create a
role? (Choose two)
- to simplify the process of creating new users using the CREATE USER xxx IDENTIFIED by yyyy statement
- to grant a group of related privileges to a user
- When the number of people using the database is very high
- to simplify the process of granting and revoking privileges
- To simplify profile maintenance for a user who is constantly traveling.
139. Which clause would you use
in a SELECT statement to limit the display to those employees whose salary is
greater than 5000?
- ORDER BY SALARY > 5000
- GROUP BY SALARY > 5000
- HAVING SALARY > 5000
- WHERE SALARY > 5000
140. Which four are correct
guidelines for naming database tables? (Choose four)
- Must begin with either a number or a letter
- must be 1-30 characters long
- Should not be an Oracle Server reserved word.
- must contain only A-Z, a-z, 0-9, _,*, and #
- must contain only A-Z, a-z, 0-9, _, $, and #
- must begin with a letter
140. Which two statements about
sequences are true? (Choose two)
- You use a NEXTVAL pseudo column to look at the next possible value that would be generated from a sequence, without actually retrieving the value.
- You use a CURRVAL pseudo column to look at the current value just generated from a sequence, without affecting the further values to be generated from the sequence.
- You use a NEXTVAL pseudo column to obtain the next possible value from a sequence by actually retrieving the value form the sequence
- You use a CURRVAL pseudo column to generate a value from a sequence that would be used for a specified database column.
- If a sequence starting from a value 100 and incremented by 1 is used by more than one application, then all of these applications could have a value of 105 assigned to their column whose value is being generated by the sequence.
- You use a REUSE clause when creating a sequence to restart the sequence once it generates the maximum value defined for the sequence.
141. Examine the description of
the MARKS table:
STD_ID NUMBER (4)
STUDENT_NAME
VARCHAR2 (30)
SUBJ1 NUMBER (3)
SUBJ2 NUMBER (3)
SUBJ1 and
SUBJ2 indicate the marks obtained by a student in two subjects
Examine
this SELECT statement based on the MARKS table:
SELECT
subj1+subj2 total_marks, std_id FROM marks WHERE subj1 > AVG (subj1) AND
subj2 > AVG (subj2) ORDER BY total_marks;
What us the result of
the SELECT statement?
- The statement executes successfully and returns the student ID and sum of all marks for each student who obtained more than the average mark in each subject.
- The statement returns an error at the SELECT clause
- The statement returns an error at the WHERE clause
- The statement returns an error at the ORDER BY clause
142. You want to display the
titles of books that meet these criteria:
1.
Purchased before January 21, 2001
2. Price
is less than $ 500 or greater than $ 900
You want to sort the result by their date of purchase,
starting with the most recently bought book. Which statement should you use?
- SELECT book_title FROM books WHERE price between 500 and 900 AND purchase_date < '21 - Jan-2001' ORDER BY purchase_date;
- SELECT book_title FROM books WHERE price IN (500, 900) AND purchase_date< '21-jan-2001' ORDER BY purchase date ASC;
- SELECT book_title FROM books WHERE price < 500 OR>900 AND purchase_date DESC;
- SELECT Book_title FROM books WHERE price < 500 OR>900 AND purchase_date<'21-JAN-2001' ORDER BY purchase date DESC;
- SELECT book_title FROM books WHERE (price< 500 OR price> 900) AND purchase date> '21 - JAN-2001' ORDER BY purchase date ASC;
143.
Click the Exhibit button to examine the structure of the EMPOLOYEES, DEPARTMENTS and TAX tables.
EMPLOYEES
EMPLOYEE_ID
NUMBER NOT NULL
primary key
EMP_NAME VARCHAR2 (30)
JOB_ID VARCHAR2 (20)
SALARY NUMBER
MGR_ID NUMBER Reference EMPLOYEE_ID
Column
DEPARTMENT_ID
NUMBER Foreign key to DEPARTMENT_ID TO column of the
DEPARTMENT table
DEPARTMENTS
DEPARTMENT_ID
NUMBER NOT NULL primary
key
DEPARTMENT_NAME
VARCHAR2 (30)
MGR_ID NUMBER Reference MGR_ID column of
the EMPLOYEES table
TAX
MIN_SALARY
NUMBER
MAX_SALARY
NUMBER
TAX_PERCENT
NUMBER
For which situation would you use a nonequijoin query?
- to find the tax percentage for each of the employees
- to list the name, job id, and manager name for all the employees
- to find the name, salary and the department name of employees who are not working with Smith
- to find the number of employees working for the Administrative department and earning less than 4000
- to display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned
144. Which operator can be used
with a multiple row subquery?
A. =
B. LIKE
C. BETWEEN
D. NOT IN
E. Is
F. <>
145. You need to perform certain data
manipulation operations through a view called EMP_DEPT_VU, which you previously
created. You
want to look at the definition of the view (the SELECT statement on which the
view was created). How do you obtain
the definition of the view?
- Use the DESCRIBE command on the EMP_DEPT VU view
- Use the DEFINE VIEW command on the EMP_DEPT VU view
- Use the DESCRIBE VIEW command on the EMP_DEPT VU view
- Query the USER_VIEWS data dictionary view to search for the EMP_DEPT_VU view
- Query the USER_SOURCE data dictionary view to search for the EMP_DEPT_VU view
- Query the USER_OBJECTS data dictionary view to search for the EMP_DEPT_VU view
146. Which statement explicitly
names a constraint?
- ALTER TABLE student_grades ADD FOREIGN KEY (student_id) REFERENCES students (student_id);
- ALTER TABLE student_grades ADD CONSTRAINT NAME=student_id_fk FOREIGN KEY (student_id) REFERENCES student(student_id);
- ALTER TABLE student_grades ADD CONSTRAINT student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id);
- ALTER TABLE student grades ADD NAMED CONSTRAINT student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id)
- ALTER TABLE student grades ADD NAME student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id)
147. You need to display the
last names of those employees who have the letter "A" as the second
character in their names. Which SQL statement displays the required results?
- SELECT last_name FROM EMP WHERE last_name LIKE'_A%;
- SELECT last_name FROM EMP WHERE last name='*A%
- SELECT last_name FROM EMP WHERE last name ='* _A%;
- SELECT last_name FROM EMP WHERE last name LIKE '* a%
148. Which two statements about creating
constraints are true? (Choose two)
- Constraint names must start with SYS_C.
- All constraints must be defined at the column level
- Constraints can be created after the table is created
- Constraints can be created at the same time the table is created
- Information about constraints is found in the VIEW_CONSTRAINTS dictionary view
149. You are granted the CREATE
VIEW privilege. What does this allow you to do?
- create a table view
- create a view in any scheme
- create a view in your schema
- create a sequence view in any schema
- create a view that is accessible by everyone
- create a view only if it is based on tables that you created
150. You created a view called
EMP_DEPT_VU that contains three columns from the
EMPLOYEES and DEPARTMENTS tables
EMPLOYEE_ID,
EMPLOYEE_NAME AND DEPARTMENT_NAME
The
DEPARTMENT_ID column of the EMPLOYEES table is the foreign key to the primary
key DEPARTMENT_ID column of the DEPARTMENTS table.
You want
to modify the view by adding a fourth column, MANAGER_Id of NUMBER data type
from the EMPLOYEES table.
How can you accomplish this task?
- ALTER VIEW emp_dept_vu (ADD manager_id NUMBER),
- MODIFY VIEW emp_dept_vu (ADD manager_id NUMBER);
- ALTER VIEW emp_dept_vu AS SELECT employee_id, employee_name Department_name, manager_id FROM employees e, departments d WHERE department_id = d.department_id;
- MODIFY VIEW emp_depat_vu AS SELECT employee_id, employee_name, Department_name, manager_id FROM employees e, departments d WHERE e.department_id = d.department_id;
- CREATE OR REPLACE VIEW emp_dept_vu AS SELECT employee_id, employee_ name, Department_name, manager _id FROM employees e, departments d WHERE e.department_id=d.department_id;
- You must remove the existing view first, and then run the CRATE VIEW command with a new column list to modify a view.
151. Examine the structure of
the EMPLOYEES and NEW_EMPLOYEES tables:
EMPLOYEES
EMPLOYEE_ID
NUMBER Primary Key
FIRST_NAME
VARCHAR2 (25)
LAST_NAME VARCHAR2 (25)
HIRE_DATE DATE
NEW
EMPLOYEES
EMPLOYEE_ID
NUMBER Primary Key
NAME VARCHAR2
(60)
Which UPDATE statement is valid?
- UPDATE new_employees SET name=(SELECT last_name|| First_name FROM employees WHERE employee_id = 180)
- B. UPDATE new_employees SET name = (SELECT Last_name || first_name FROM employees) WHERE employee_id = 180
- C. UPDATE new_employees SET name = (SELECT last_name|| First_name FROM employees WHERE employee_id = 180 WHERE employee_id = (SELECT employee_id FROM new employees),
- D. UPDATE new_employees SET name = (SELECT last name|| First_name FROM employees WHERE employee_id= (SELECT employee_id WHERE employee_id FROM new_employees)) WHERE employee_id = 180,
152. You need to produce a
report for mailing labels for all customers. The mailing label must have only
the customer name and address. The CUSTOMER table has these columns:
CUST_ID NUMBER (4) NOT NULL
CUST_NAME VARCHAR2 (100) NOT NULL
CUST_ADDRESS
VARCHAR2 (150)
CUST_PHONE
VARCHAR (20)
Which SELECT statement accomplishes this task?
- SELECT * FROM customers
- SELECT name, address FROM customers;
- SELECT id, name, address, phone FROM customers;
- SELECT cust_name, cust_address FROM customers;
- SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
153. Which substitution variable would you use
if you want to reuse the variable value without prompting the user each time?
- &
- ACCEPT
- PROMPT
- &&
154. Examine the structure of
the EMPLOYEES table:
Column name Data
type Remarks
EMPOYEE_ID NUMBER
NOT NULL, Primary Key
EMP_NAME VARCHAR2
(30)
JOB_ID VARCHAR2 (20) NOT NULL
SAL NUMBER
MGR_ID NUMBER
References
EMPLOYEE_ID column
DEPARTMENT_ID NUMBER Foreign key to
DEPARTMENT_ID column Of the DEPARTMENTS table
You need to create a view called EMP_VU that allows the
users to insert rows through the view. Which SQL statement, when used to create
the EMP_VU view, allows the users to insert rows?
- CREATE VIEW emp_Vu AS SELECT employee_id, emp_name, Department_id FROM employees WHERE mgr_id IN (102,120);
- CREATE VIEW emp_Vu AS SELECT employee_id, emp_name, job_id, Department_id FROM employees WHERE mgr_id IN (102, 120);
- CREATE VIEW emp_Vu AS SELECT department_id, SUM(sal) TOTAL SAL FROM employees WHERE mgr_id IN (102, 120) GROUP BY department_id;
- CREATE VIEW emp_Vu AS SELECT employee_id, emp_name, job_id, DISTINCT department_id FROM employees
155. What is true about the WITH GRANT OPTION
clause?
- It allows a grantee DBA privileges
- B. It is required syntax for object privileges
- It allows privileges on specified columns of tables
- It is used to grant an object privilege on a foreign key column
- It allows the grantee to grant object privileges to other users and roles
156. The STUDENT_GRADES table has these columns
STUDENT_ID NUMBER
(12)
SEMESTER_END DATE
GPA NUMBER
(4, 3)
The registrar has asked for a report on the average grade
point average (GPA) for students enrolled during semesters that end in the year
2000. Which statement accomplishes this?
A. SELECT
AVERAGE(gpa) FROM student_grades WHERE semester_end > '01-JAN-2000' and
semester end < '31-DEC-2000'
- SELECT COUNT (gpa) FROM student grades WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000'
- SELECT MID (gpa) FROM student_grades WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000' D. SELECT AVG (gpa) FROM student_grades WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000'
- SELECT SUM (gpa) FROM student_grades WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000'
- SELECT MEDIAN (gpa) FROM student_grades WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000'
157. In which scenario would Top N analysis be
the best solution?
- You want to identify the most senior employee in the company
- You want to find the manager supervising the largest number of employees
- You want to identify the person who makes the highest salary of all employees
- You want to rank the top three sales representatives who have sold the maximum number of products
158. Click the Exhibit button to examine the
data of the EMPLOYEES table.
EMPLOYEES (EMPLOYEE_ID is the primary key.
MGR_ID is the ID of managers and refers to the EMPLOYEE_ID)
EMPLOYEE_ID - EMP_NINE - DEPT_ID - MGR_ID - JOB_ID - SALARY
101 - Smith - 20 - 120 - SA_REP - 4000
102 - Martin - 10 - 105 - CLERK - 2500
103 - Chris - 20 - 120 - IT_ADMIN - 4200
104 - John - 30 - 108 - HR_CLERK - 2500
105 - Diana - 30 - 108 - HR_MGR - 5000
106 - Bryan - 40 - 110 - AD_ASST - 5000
108 - Jennifer - 30 - 110 - HR_DIR - 6500
110 - Bob - 40 - ** - EX_DIR - 8000
120 - Ravi - 20 - 110 - SA_DIR - 6500
Which statement lists the ID, name, and salary of the
employee, and the ID and name of the employee's manager, for all the employees
who have a manager and earn more than 4000?
- SELECT employee_id "Emp_id", emp_name "Employee", salary, employee_id "Mgr_id", emp_name "Manager" FROM employees WHERE salary > 4000;
- SELECT e.employee_id "Emp_id", e.emp_name "Employee" ,e.salary, m.employee_id "Mgr_id", m.emp_name "Manager" FROM employees e, employees m WHERE e.mgr_id = m.mgr_id AND e.salary > 4000;
- SELECT e.employee_id "Emp_id", e.emp_name "Employee" ,e.salary, m.employee_id "Mgr_id", m.emp_name "Manager" FROM employees e, employees m WHERE e.mgr_id = m.employee_id AND e.salary > 4000;
- SELECT e.employee_id "Emp_id", e.emp_name "Employee" ,e.salary, m.mgr_id "Mgr_id", m.emp_name "manager" FROM employees e, employees m WHERE e.mgr_id = m.employee_id AND e.salary > 4000;
- SELECT e.employee_id "Emp_id", e.emp_name "Employee" ,e.salary, m.mgr_id "Mgr_id", m.emp_name "Manager" FROM employees e, employees m WHERE e.employee_id = m.employee_id AND e.salary > 4000;
159. What does the TRUNCATE statement do?
- removes the table
- removes all rows from a table
- shortens the tale to 10 rows
- removes all columns from a table
- removes foreign keys from a table
160. The ORDERS table has these columns
ORDER_ID NUMBER
(4) NOT NULL
CUSTOMER_ID NUMBER
(12) NOT NULL
ORDER_TOTAL NUMBER
(10, 2)
The ORDERS table tracks the Order number, the order total
and the customer to whom the Order belongs. Which two statements retrieve
orders with an inclusive total that ranges between 100.00 and 200.00 dollars?
(Choose Two).
A.
SELECT customer_id, order_id, order_total FROM
orders RANGE ON order_total (100 AND 2000) INCLUSIVE
B.
SELECT customer_id, order_id, order_total FROM orders
HAVING order total BETWEEN 100 and 2000
C.
SELECT customer_id, order_id, order_total
FROM orders WHERE order_total BETWEEN 100 and 2000
D. SELECT
customer_id, order_id, order_total FROM orders WHERE order_total >= 100 and
<=2000
E.
SELECT customer_id, order_id, order _total
FROM orders WHERE order_total>= 100 and order_total <=2000.
161. The EMPLOYEES table contains these columns:
LAST_NAME VARCHAR2
(25)
SALARY NUMBER
(6, 2)
COMMISSION_PCT NUMBER
(6)
You need to write a query that will produce these results:
1. Display
the salary multiplied by the commission_pct
2. Exclude
employees with a zero commission_pct
3. Display
a zero for employees with a null commission value
Evaluate
the SQL statement:
SELECT
LAST_NAME, SALARY * COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT
NULL;
What does the statement provide?
- all of the desired results
- two of the desired results
- one of the desired results
- an error statement
162. A subquery can be used to _________.
- create groups of data
- sort data in a specific order
- convert data to a different format
- retrieve data based on an unknown condition
163. Which clause should you use to exclude group
results?
A. WHERE
B. HAVING
C. RESTRICT
D. GROUP BY
E. ORDER BY
164. Scott
issues the SQL statements:
CREATE
TABLE dept (deptno number (2) dname VARCHAR2 (14) loc VARCHAR2 (13));
GRANT
SELECT ON DEPT TO SUE;
If Sue
needs to select from Scott's DEPT table, which command should she use?
A. SELECT * FROM DEPT
B. SELECT * FROM SCOTT.DEPT
C. SELECT * FROM DBA.SCOTT.DEPT.
D. SELECT * FROM ALL_USERS WHERE USER_NAME = 'SCOTT' AND
TABLE NAME= 'DEPT';
165.
Examine the data in the EMPLOYEES and EMP_HIST tables:
EMPLOYEES
EMPLOYEE_IDNAME
DEPT_ID MGR_ID JOB_ID SALARY
101 -
Smith - 20 - 120 - SA_REP - 4000
102 -
Martin - 10 - 105 - CLERK - 2500
103 -
Chris - 20 - 120 - IT_ADMIN - 4200
104 - John
- 30 - 108 - HR_CLERK - 2500
105 -
Diana - 30 - 108 - IT_ADMIN - 5000
106 -
Smith - 40 - 110 - AD_ASST - 3000
108 -
Jennifer - 30 - 110 - HR_DIR - 6500
110 - Bob
- 40 - ** - EX_DIR - 8000
120 - Ravi
- 20 - 110 - SA_DIR - 6500
EMP_HIST
EMPLOYEE_ID
- NAME - JOB_ID - SALARY
101 -
Smith - SA_CLERK - 2000
103 -
Chris - IT_CLERK - 22
104 - John
- HR_CLERK - 2000
106 -
Smith - AD_ASST - 3000
108 -
Jennifer - HR_MGR – 4500
The EMP_HIST table is updated at the end of every year.
The employee ID, name, jobID, and salary of each existing employee are modified
with the latest data. New employee details are added to the table. Which
statement accomplishes this task?
- UPDATE emp_hist SET employee_id, name, job_id, salary = (SELECT employee_id, name, job_id, salary FROM employees) WHERE employee_id IN (SELECT employee_id FROM employees);
- MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT VALUES (e.employee_id, e.name, e.job_id id, e.salary);
- MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE emp_hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employee_id, e.name, e.job_id, e.salary);
- MERGE INTO emp_hist eh USING employees e WHEN MATCHED THEN UPDATE emp_hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employee_id, e.name, e.job_id, e.salary);
166. You need to calculate the total of all salaries in
the accounting department. Which group function should you use?
A. MAX
B. MIN
C. SUM
D. COUNT
E. TOTAL
F. LARGEST
167. The EMP table has these columns:
ENAME VARCHAR2
(35)
SALARY NUMBER
(8, 2)
HIRE_DATE DATE
Management wants a list of names of employees who have been
with the company for more than five yeas. Which SQL statement displays the
required results?
- SELECT ENAME FROM EMP WHERE SYSDATE-HIRE_DATE>5
- SELECT ENAME FROM EMP WHERE HIRE_DATE-SYSDATE > 5
- SELECT ENAME FROM EMP WHERE (SYSDATE-HIRE_DATE)/365 > 5
- SELECT ENAME FROM EMP WHERE (SYSDATE-HIRE_DATE)* 365 > 5
168. You would like to display
the system date in the format *Monday, 01 June, 2001* Which SELECT statement
should you use?
- SELECT TO_DATE (SYSDATE, 'FMDAY, DD Month, YYYY') FROM dual
- SELECT TO_CHAR(SYSDATE, 'FMDD, DY Month 'YYY') FROM dual
- SELECT TO_CHAR(SYSDATE, 'FMDay, DD Month YYYY') FROM dual
- SELECT TO_CHAR(SYSDATE, 'FMDAY, DDD Month, YYYY') FROM dual
- SELECT TO_DATES(SYSDATE,'FMDY, DDD Month, YYYY') FROM dual
169. The CUSTOMERS table has these columns:
CUSTOMER_ID
NUMBER (4) NOT NULL
CUSTOMER_NAME
VARCHAR2 (100)
STREET_ADDRESS
VARCHAR2 (150)
CITY_ADDRESS
VARCHAR2 (50)
STATE_ADDRESS
VARCHAR2 (50)
PROVINCE_ADDRESS
VARCHAR2 (50)
COUNTRY_ADDRESS
VARCHAR2 (50)
POSTAL_CODE
VARCHAR2 (12)
CUSTOEMR_PHONE
VARCHAR2 (20)
Which statement finds the rows in the CUSTOMERS table that do not have a postal code
A.
SELECT customer_id, customer_name FROM customers
WHERE postal_code CONTAINS NULL
B.
SELECT customer_id, customer name FROM customers
WHERE posta_code='_______'
C.
SELECT customer_id, customer_name FROM
customers WHERE postal_code IS NULL
D. SELECT
customer_id, customer_name FROM customers WHERE postal code IS NVL
E.
SELECT customer_id, customer_name FROM customers
WHERE postal_code=NULL
170. You define a multiple-row subquery in the WHERE
clause of an SQL query with a comparison operator"=" What happens
when the main query is executed?
- the main query executes with the first value returned by the subquery
- the main query executes with the last value returned by the subquery
- the main query executes with all the values returned by the subquery
- The main query fails because the multiple-row subquery cannot be used with the comparison operator.
- You cannot define multiple-row subquery in the WHERE clause of a SQL query
171. Which three statements correctly describe the
functions and use of constraints? (Choose three)
- constraints provide data independence
- constraint make complex queries easy
- constraints enforce rules at the view level
- constraints enforce rules at the table level
- constraints prevent the deletion of a table if there are dependencies
- constraints prevent the deletion of an index if there are dependencies
172. Which two are character
manipulation functions? (Choose two)
A. TRIM
B. REPLACE
C. TRUNC
D. TO_DATE
E. MOD
F. CASE
173. Examine the data in the EMPLOYEES table.
EMPLOYEES
EMPLOYEE_ID - EMP_NAME - DEPT_ID - MGR_ID - JOB_ID - SALARY
101 - Smith - 20 - 120 - SA_REP - 4000
102 - Martin - 10 - 105 - CLERK - 2500
103 - Chris - 20 - 120 - IT_ADMIN - 4200
104 - John - 30 - 108 - HR_CLERK - 2500
105 - Diana - 30 - 108 - IT_ADMIN - 5000
106 - Smith - 40 - 110 - AD.ASST - 3000
108 - Jennifer - 30 - 110 - HR_DIR – 6500
110 - Bob - 40 - *** - EK_DIR - 8000
120 - Ravi - 20 - 110 - SA_DIR - 6500
On the EMPLOYEES table,
EMPLOYEE_ID is the primary key.
MGR_ID is the ID of managers and refers to the EMPLOYEE_ID.
The JOB_ID column is a NOT NULL column.
Evaluate this DELETE statement: DELETE employee_id,
salary, job_id FROM employees WHERE dept_id = 90; Why does the DELETE statement
fail when you execute it?
- There is no row with dept_id 90 in the EMPLOYEES table.
- You cannot delete the JOB_ID column because it is a NOT NULL column.
- You cannot specify column names in the DELETE clause of the DELETE statement.
- You cannot delete the EMPLOYEE_ID column because it is the primary key of the table.
174. Which two
statements accurately describe a role? (Choose two)
- a role can be given to a maximum of 1000 users
- a user can have access to a maximum of 10 roles
- A role can have a maximum of 100 privileges contained in it.
- Privileges are given to a role by using the CREATE ROLE statement.
- A role is a named group of related privileges that can be granted to the user
- A user can have access to several roles, and several users can be assigned the same role.
175. You added a PHONE-NUMBER column of NUMBER data type
to an existing EMPLOYEES table. The EMPLOYEES table already contains records of
100 employees. Now, you want to enter the phone numbers of each of the 100
employees into the table some of the employees may not have a phone number
available. Which data manipulation operation do you perform?
A. MERGE
B. INSERT
C. UPDATE
D. ADD
E. ENTER
F. You cannot enter the phone number for the existing
employee records
176. The CUSTOMERS table has these columns:
CUSTOMER_ID
NUMBER (4) NOT NULL
CUSTOMER_NAME
VARCHAR2 (100) NOT NULL
STREET_ADDRESS
VARCHAR2 (150)
CITY_ADDRESS
VARCHAR2 (50)
STATE_ADDRESS
VARCHAR2 (50)
PROVINCE_ADDRESS
VARCHAR2 (50)
COUNTRY_ADDRESS
VARCHAR2 (50)
POSTE_CODE
VARCHAR2 (12)
CUSTOMER_PHONE
VARCHAR2 (20)
THE CUSTOMER_ID column is the
primary key for the table which two statements find the number of customer?
(Choose two.)
- SELECT TOTAL (*) FROM customers;
- SELECT COUNT (*) FROM customers;
- SELECT TOTAL (customer_id) FROM customer;
- SELECT COUNT(customer_id) FROM customer;
- SELECT COUNT(customers) FROM customers;
- SELECT TOTAL (customer_name) FROM customers;
177. in a SELECT statement that includes a WHERE clause,
where is the GROUP BY clause placed statement?
- immediately after the SELECT clause
- before the WHERE clause
- before the FROM clause
- after the ORDER BY clause
- after the WHERE clause
178. For which two constrains does the Oracle Server
implicitly create a unique index? (Choose two)
A. NOT NULL
B. PRIMARY KEY
C. FOREIGN KEY
D. CHECK
E. UNIQUE
179. Which / SQL* Plus feature can be used to replace
values in the where clause?
- Substitution variables
- replacement variables
- prompt variables
- instead-of variables
- This feature cannot be implemented through / SQL*Plus
180. Evaluate the SQL statement:
SELECT ROUND (TRUNC (MOD (1600, 10),-1), 2) FROM
dual;
What will be displayed?
A. 0
B. 1
C. 0.00
D. an error statement
181. Examine the structure of the EMPLOYEES table:
EMPLOYEE_ID
NUMBER Primary Key
FIRST_NAME
VARCHAR2 (25)
LAST_NAME VARCHAR2 (25)
DEPARTMENT_ID
NUMBER
SALARY NUMBER
What is the correct syntax for an inline view?
A. SELECT a last_name, a salary, a department_id, b.maxsal
FROM employees a,
(SELECT department_id, max (salary) maxsal FROM employees
GROUP BY department_id)b WHERE a department_id = department-id AND a_salary
Answer: A
182. Examine the structure of the EMPLOYEES table:
EMPLOYEE_ID
NUMBER NOT NULL
EMP_ID VARCHAR2 (30)
JOB_ID VARCHAR2
(20) DEFAULT 'SA_REP'
SAL NUMBER
COMM_PCT NUMBER
MGR_ID NUMBER
DEPARTMENT_ID
NUMBER
You need
to update the records of employees 103 and 115.
The UPDATE
statement you specify should update the rows with the values specified below:
JOB_ID:
Default value specified for this column definition
SAL:
maximum salary earned for the job ID SA_REP
COMM_PCT:
Default value is specified for the column, the value should be NULL
DEPARTMENT_ID:
Supplied by the user during run time through substitution variable
Which UPDATE statement meets the requirements?
- UPDATE employees SET job_id=DEFAULT AND Sal=(SELECT MAX(sal) FROM employees WHERE job_id='SA_REP' AND comm_pct=DEFALUT AND department_id =&did WHERE employee_id IN (103, 115),
- UPDATE employees SET job_id = DEFAULT AND Sal = MAX(sal) AND comm_pct = DEFAULT OR NULL AND department _id = & did WHERE employee_id IN (103,115) AND job_id = 'SA_REP'
- UPDATE employees SET job_id = DEFAULT Sal = (SELECT MAX (sal) FROM employees WHERE job_id = 'SA_REP') comm_pct = DEFAULT, department _id = &did WHERE employee_id IN (103,115)
- UPDATE employees SET job_id = DEFAULT sal = MAX (sal) comm_pct = DEFAULT department_id = &did WHERE employee_id IN (103,115) AND job_id = 'SA_REP' E. UPDATE employees SET job_id = DEFAULT Sal = (SELECT MAX(sal) FROM employees WHERE job_id = 'SA_REP') comm_pct = DEFAULT OR NULL, department_id = &did WHERE employee_id IN (103,115)
183. Which data dictionary table should you query to view
the object privileges granted to the user on specific columns?
- USER_TAB_PRIVS_MADE
- USER_TAB_PRIVS
- USER_COL_PRIVS_MADE
- USER_COL_PRIVS
184. Which three are DATETIME data types that can be used
when specifying column definitions? (Choose three)
- TIMESTAMP
- INTERVAL MONTH TO DAY
- INTERVAL DAY TO SECOND
- INTERVAL YEAR TO MONTH
- TIMESTAMP WITH DATABASE TIMEZONE
185. Click the Exhibit button and examine the data from
the ORDERS and CUSTOMERS tables.
ORDERS
ORD_ID - ORD_DATE - CUST_ID - ORD_TOTAL
100 - 12.JAN-2000 - 15 - 10000
101 - 09-MAR-2000 - 40 - 8000
102 - 09-MAR-2000 - 35 - 12500
103 - 15-MAR-2000 - 15 - 12000
104 - 25-JUN-2000 - 15 - 6000
105 - 18-JUL-2000 - 20 - 5000
106 - 18-JUL-2000 - 35 - 7000
107 - 21-JUL-2000 - 20 - 6500
108 - 04-AUG-2000 - 10 - 8000
CUSTOMERS
CUST_ID - CUST_NAME - CITY
10 - Smith - Los Angeles
15 - Bob - San Francisco
20 - Martin - Chicago
25 - Mary - New York
30 - Rina - Chicago
35 - Smith - New York
40 - Linda - New York
Evaluate the SQL statement:
SELECT *
FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name =
'Smith')
What is the result when the query is executed?
- ORD_ID ORD_DATE CUST_ID ORD_TOTAL 102 09-MAR-2000 35 12500 106 18-JUL-2000 35 7000 108 04-AUG-2000 10 8000
- ORD_ID ORD_DATE CUST_ID ORD_TOTAL 102 09-MAR-2000 35 12500 106 18-JUL-2000 35 7000
- ORD_ID ORD_DATE CUST_ID ORD_TOTAL 108 04-AUG-2000 10 8000
- The query fails because the subquery returns more than one row.
- The query fails because the outer query and the inner query are using different tables.
186. Which syntax turns an
existing constraint on?
- ALTER TABLE table_name ENABLE constraint_name
- ALTER TABLE table_name STATUS = ENABLE CONSTRAINT constraint_name
- ALTER TABLE table_name ENABLE CONSTRAINT constraint_name
- ALTER TABLE table_name STATUS ENABLE CONSTRAINT constraint_name
- ALTER TABLE table_name TURN ON CONSTRAINT constraint_name
- ALTER TABLE table_name TURN ON CONSTRAINT constraint_name
187. Which two statements about views are true? (Choose
two)
- A view can be created as read only
- A view can be created as a join on two or more tables.
- A view cannot have an ORDER BY clause in the SELECT statement.
- A view cannot be created with a GROUP BY clause in the SELECT statement.
- A view must have aliases defined for the column names in the SELECT statement.
188. the database administrator of your company created a
public synonym called HR for the HUMAN_RESOURCES table of the GENERAL schema,
because many users frequently use this table. As a user of the database, you
created a table called HR in your schema. What happens when you execute this
query?
SELECT *
FROM HR;
- you obtain the results retrieved from the public synonym HR created by the database administrator
- You obtain the results retrieved form the HR table that belongs to your schema.
- you get an error message because you cannot retrieve from a table that has the same as a public synonym
- You obtain the results retrieved from both the public synonym HR and the HR table that belongs to your schema, as a Cartesian product.
- You obtain the results retrieved form both the public synonym HR and the HR table that belongs to your schema, as a FULL JOIN.
189.
You need to give the MANAGER role the ability to select from insert into and
modify existing rows in the STUDENT_GRADES table.
Anyone
given this MANAGER role should be able to pass those privileges on to others.
Which statement accomplishes this?
- GRANT select, insert, update ON student_grades TO manager;
- GRANT select, insert, update ON student_grades TO ROLE manager
- GRANT select, insert, modify ON student_grades TO manager WITH GRANT OPTION;
- GRANT select, insert, update ON student_grades TO manager WITH GRANT OPTION
- GRANT select, insert, update ON student_grades TO ROLE manager WITH GRANT OPTION;
- GRANT select, insert, modify ON student_grades TO ROLE manager WITH GRANT OPTION
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